A comparison of Strings in Java is done character by character. Each character has a specific ranking to it based on where it appears in the Unicode character table (for this case, we can use ASCII, since it’s English). “1” would be considered less than “7”, as well as “T”. To invoke (place this inside … Read more
Strings are comparable in a lexicographic order (i.e., the order they’d appear in a dictionary). If you want to implement a Comparator for clothes sizes, you’d have to write the logic yourself. E.g.: public class ClothesSizeComparator implements Comparator<String> { private static final List<String> SIZES = Arrays.asList(“XS”, “S”, “M”, “L”, “XL”, “XXL”, “3XL”); @Override public int … Read more
If you want to compare keys of Dictionary, then: var dict1 = new Dictionary<string, List<string>>(); var dict2 = new Dictionary<string, List<string>>(); // something.. if (dict1.Keys.SequenceEqual(dict2.Keys)) { // your code } If you want to compare values of Dictionary, then: var dict1 = new Dictionary<string, List<string>>(); var dict2 = new Dictionary<string, List<string>>(); // something.. var d1Keys … Read more
here’s how I would implement it: window.onload=function(){ var array1 = [1, 2, 3, 4, 5, 6] var array2 = [3, 4, 5, 6, 7, 8] var result = [] var resultCount=0; for (var i1 = 0; i1 < array1.length; i1++) { var comparedElement = array1[i1]; var isUnique = true; for (var i2 = 0; i2 … Read more
awk one liner awk ‘{if(NR>1)system(“grep -w ^”$2″ <file2>”);}’ <file1> Also many other solutions are there, check join or in awk itself without using grep, simply by storing the first files content in an array, it can be done, 1 solved bash: compare 2 files, then output third file with same pattern [closed]
List<Integer> data = Arrays.asList(23,6,13); Collections.sort(data); Collections.reverse(data) data = data.sublist(0,2); System.out.println(data); 6 solved Finding the sum of the two greatest numbers of 3 [closed]
import re caselines_index = [] cases = [] readlines = [] def read(in_file): global cases global caselines_index global readlines with open(in_file, ‘r’) as file: for line in file.readlines(): readlines.append(line.strip()) for line in readlines: case_search = re.search(“case\s\”.+?\”\:\s”, line) if case_search: caselines_index.append(readlines.index(line)) #print caselines_index caselines_index_iter = iter(caselines_index) int_line_index = int(next(caselines_index_iter)) int_next_index = int(next(caselines_index_iter)) while True: try: case_text=” … Read more
Your last addition to the post makes it a bit more clear. You wait for 3 child processes like this: wait(&team1); wait(&team2); wait(&team3); So team1..team3 will have the exit code of those processes. But the function wait does not wait for any specific process, the first wait will return the exit code of the first … Read more
Here are a couple of ideas. This is what I think your data look like? before <- data.frame(val=c(11330,2721,52438,6124), lab=c(“STAT1″,”STAT2″,”STAT3″,”SUZY”)) after <- data.frame(val=c(17401,3462,0,72), lab=c(“STAT1″,”STAT2″,”STAT3″,”SUZY”)) Combine them into a single data frame with a period variable: combined <- rbind(data.frame(before,period=”before”), data.frame(after,period=”after”)) Reformat to a matrix and plot with (base R) dotchart: library(reshape2) m <- acast(combined,lab~period,value.var=”val”) dotchart(m) Plot with … Read more
Suppose we have 2 list x = [‘3’, ‘1’] y = [‘1’, ‘3’] Solution-1: You can simply check whether the multisets with the elements of x and y are equal: import collections collections.Counter(x) == collections.Counter(y) This requires the elements to be hashable; runtime will be in O(n), where n is the size of the lists. … Read more
First you would need to make a method in your custom class that accepts an object of the same class and tests whether the imputed object has the same values as the object which is calling the method. Then just loop through the array and see if the object is equal to another object. This … Read more
Introduction Java is a powerful programming language that can be used to solve a variety of problems. One such problem is getting the difference between two arrays. This can be done in a few different ways, depending on the type of data in the arrays and the desired output. In this article, we will discuss … Read more
This looks like a terrible database design, so I would highly recommend changing it! Having duplicate IDs hurts me deeply. But, here’s a MySQL query that could get the result you are after: SELECT `ID`, `Date`, CONCAT(MIN(`Time`), ‘ ‘, MAX(`Time`)) AS `Time` FROM `test` GROUP BY `ID`, `Date`; 7 solved How to compare the current … Read more
Please note that the function you are searching for is a validator. Just coded a simple on for you : $data = array( ‘size’ => ‘small’, ‘color’ => ‘red’, ); $validator = array( array( ‘name’ => ‘size’, ‘value’ => ‘small’, ), array( ‘name’ => ‘color’, ‘value’ => ‘red’, ), ); function validateData(array $data, array $validator, … Read more
You are passing date and time in to your procedure, but when you convert those to dynamic SQL, you are using format 101, which removes the time portion. Try changing the 101 to 126 (there are 2 places within your code where 101 is used, make sure you change both of them. 0 solved compare … Read more