You have to initialized the variable before to use them. decimal days = 0.0; decimal registrationFee = 0.0; decimal lodgingFee =0.0; decimal total = 0.0; decimal lodgingCal= 0.0; 2 solved What to do with my error? [closed]
Here is an approach : int cur=1,num=1; for(int i=0;i<4;i++) { for(int j=0;j<cur;j++) { if(j!=0) printf(“*”); printf(“%d”,num++); } printf(“\n”); cur++; } cur=4,num=10; for(int i=0;i<4;i++) { int temp=num-cur+1; for(int j=0;j<cur;j++) { if(j!=0) printf(“*”); printf(“%d”,temp++); } printf(“\n”); num-=cur; cur–; } solved How do print the following pattern in C/C++?
in class 1 create a method like this public void Update() { // Put logic here to update position for your ball on the curve. } Call update from class 2 when you increment the time. private void Timer1_Tick(object sender, EventArgs e) { Class1.Update(); a += 1 } 1 solved Uppdating a variable [closed]
This method is quick and clean, basically read in values the number of times specified, and each time the number is greater than the current maximum, replace max with the value read. int main() { int num_entries; float num; float max = 0; cin >> num_entries; while (num_entries– > 0){ cin >> num; if (num … Read more
% operator is remainder operator. It calculates the remainder when you divide first operand to second one. 10 = 25 * 0 + 10 You need to use / operator with at least one floating point number to get 0.4 as a result. Otherwise, this operators calculates integer division for two integer operands and it’s … Read more
#include <stdio.h> int main(void){ int T; scanf(“%d”, &T); for(int i = 1; i <= T; ++i){ int marks[101] = {0}; int max = -1; int n, mark; scanf(“%d”, &n); for(int j = 0; j < n; ++j){ scanf(“%d”, &mark); if(mark > max) max = mark; ++marks[mark]; } printf(“case %d : max = %d, frequency = … Read more
You are doing the math wrong. The answer would be 1+2+3+4+ … upto n-1 and not 1*2*3 … n solved How many times will “Hello World” be printed?
Random act of madness kindness: Live On Coliru #include <fstream> #include <set> struct Person { std::string name; std::string nationality; std::set<std::string> hobbies; friend std::istream& operator>>(std::istream& is, Person& into) { size_t n = 0; if (getline(is, into.name) && getline(is, into.nationality) && is >> n && is.ignore(1024, ‘\n’)) { while (n–) { std::string hobby; if (getline(is, hobby)) into.hobbies.insert(hobby); … Read more
From your code – assuming the function stats is being executed one per game iteration. the gamesStruct local variable is being destroyed at end of stats and being declared (and initialized) again and again. this is why the previous result is cleared. you should declare the gamesStruct at tge calling API and pass it by … Read more
I’d rather write a more useful and correct version of this code #include <stdio.h> int main() { int n1, n2, ans; char op; scanf(“%d %c %d”, &n1, &op, &n2); switch (op) { case ‘+’: ans = n1 + n2; break; case ‘-‘: ans = n1 – n2; break; case ‘*’: ans = n1 * n2; … Read more
Consider the case when you insert at the end of the list. Then you get // current = NULL current->next = nextnode; // is ((struct node*)NULL)->next = nextnode; solved I am getting Segmentation fault (core dumped) for below code.Please help me out [closed]
Restate problem: 1) Compute F = largest proper factor of X 2) Output X-F Instead of directly searching for the largest proper factor, apply three trivial optimizations (maybe something more advanced will be needed, but first see if three trivial optimizations are enough). A) Find S = smallest factor of X greater than 1. Output … Read more
double* ptr; ptr = (double*)malloc(10*_R_CONST*sizeof(double)+2048); This is the C way of allocating an array dynamically at runtime, the Java equivalent is double[] ptr = new double[10*_R_CONST+256]; (Note that Java does not need the sizeof(double) factor, since it allocates objects, not bytes. For the same reason, the 2048 byte buffer shrinks to 256 doubles.) Similar, the … Read more
getch() is not an ANSI C function. You need to include the header file <conio.h> to use it. Or best of all, just use the ANSI conformant function getchar(). 4 solved What’s wrong with my program (getch function)?
When N > 100, h is accessed to an index greater than 100, inside the nested for loop h[k][i][j]=100; but h is defined as double h[2][100][100]; You are going out of bounds for h If you want N as greater than 100 you need to redefine h or malloc it. 1 solved Program working fine … Read more