[ad_1] Every #include directive including something from the C++ standard library “loads” the entities into the std namespace (or some other namespace like this). The namespace helps preventing global namespace pollution – by keeping everything in a seperate namespace, identifier collisions are rendered impossible. In the <vector> file, then there is something like namespace std … Read more
[ad_1] Why there is output by pressing enter , without reaching EOF in file copy program ,example in the book “THE C PROGRAMMING LANGUGE BY DENNIS RITCHIE” [ad_2] solved Why there is output by pressing enter , without reaching EOF in file copy program ,example in the book “THE C PROGRAMMING LANGUGE BY DENNIS RITCHIE”
[ad_1] You probably copy pasted functions but forgot to include appropriate headers (newbie mistake). Just try this: #include <iostream> #include <vector> #include <complex> using namespace std; int main() { cout<<“Hello World”; return 0; } 2 [ad_2] solved How to include std::vector, std::complex, std::cout, etc. in Visual Studio C++ [closed]
[ad_1] You don’t need arguments in GetMenuOption() and GetValue() methods. And here is loop (it is needed if you want to process more than one temperature) with switch: while (true) { DisplayMenu(); var letter = GetMenuOption(); var fromString = String.Empty; var toString = String.Empty; if (letter == ‘X’) { break; } var fromValue = GetValue(); … Read more
[ad_1] You’ve got an else with no attached if. Presumably, the println are supposed to be inside the following block, rather than being the entire body of the if statement: if(ID.indexOf(msg)>=0) { Serial.println(“Access granted.”); // <<< inside if body digitalWrite(10, HIGH); delay(2000); digitalWrite(10, LOW); } else { Serial.println(“Access denied.”); // <<< inside else body digitalWrite(9, … Read more
[ad_1] !something_here will evaluate to 0 except the case when something_here is 0. Since 0 < a, (0 < 5), a gets a value of true, which is 1, when parsed as float. [ad_2] solved a = !5 < a; what is exactly done in this line of code?
[ad_1] You can use if (a != 2) cout<<“2*”; else cout<<“2”; instead of cout<<“2*”; [ad_2] solved How to prevent a final cout in a loop from being executed?
[ad_1] Something like this? string output = DateTime.Now.ToString(“yyyy-0MM-ddTHH:mm:ss:fffZ”); I’m not sure about the “Z”, if you wanted some time zone info. I zero padded the month like your example. Obviously there would never be a needed third decimal place. 1 [ad_2] solved Getting specific datetime format in C#
[ad_1] bool doit(int list[], int size); The function doit takes an array of integers as first parameter, and the size of the array (which is an integer) as second parameter. It returns a boolean (true or false). This sort of function prototype is typically used to access each element of the array within a for … Read more
[ad_1] Why do you want to do this? Just take as input an integer array without commas. But if you want, then here is how to achieve it. You can use a character array to keep such data. An integer array will not do. Your input will be stored as: char a[3]; a[0]=’1′; a[1]=’,’; a[2]=’2′; … Read more
[ad_1] The problem is this line: cout << karatsuba(123, 456, counter) << ” ” << counter << endl; Try instead cout << karatsuba(123, 456, counter); cout << ” ” << counter << endl; the problem is cout, count is still 0 when it prints. 3 [ad_2] solved C++ – Recursive counter [closed]
[ad_1] That code is not a declaration, but it can be interpreted as an expression. (*I_dont_know())[(int) ((*ptr))] Call the function I_dont_know with no arguments. This function returns a pointer to something. Dereference the returned pointer to get some object. Meanwhile, dereference the value of ptr and cast it to an int value. Then pass that … Read more
[ad_1] var list = new List<string>(); for (int i = 0; i < 10; i++) { list.Add(string.Empty); } gv_Others.DataSource = list; gv_Others.DataBind(); This is the quickest and dirtiest way I could think of, would I write something like this? No. But then I’m sure you have your reasons, would have been better if you’d written … Read more
[ad_1] Well that’s because c_str() returns a const char * and not a char * Just change the line to: const char * c = s.c_str(); and the function declaration to std::string Exec(const char* cmd) Like noted before and you’re good to go. See it live here. [ad_2] solved invalid conversion from ‘const char*’ to … Read more
[ad_1] Just a wild guess based on the symptoms only. A c++ string is a much more complex object than is a mere C char *. In this particular use case, it has a true length and can contain NULL characters, whereas by convention a C string (char *) is ended with a NULL. That … Read more