You could define a filter function that checks if there is one HTML tag with a attribute value equal to value: def your_filter(tag, value): for key in tag.attrs.keys(): if tag[key] == value: return True return False # alternatively as one liner: def your_filter(tag, value): return any(tag[key] == value for key in tag.attrs.keys()) Then, you could … Read more
“Unreachable statement” means that there is no path in your code that can get you to this line in your program. It has nothing to do with protected fields. Check, if there is a return statement before your a+=1 that always exits your method before this line is ever reached. Or, if your a+=1 is … Read more
There are a few issues on your snippet. You are not loading jQuery library so you cannot select a DOM element(such as p.slider-price) like $(“p.slider-price”). To fix that, you should load the jQuery library (in fiddle you do that by choosing it from the frameworks & extensions menu). Than, using jQuery you will be able … Read more
Old versions won’t support these attributes. Download latest version from notepad-plus-plus.org or click below link to download. https://notepad-plus-plus.org/download/ Please see the difference of the attribute coloring between two versions of Notepad++ : Before installation: After installation: 4 solved Max, Min and Step attributes
When I understood the problem right then you can hold the last start number in a local variable: private int lastStartNumber = 0; private int getNextStartNumber(){ lastStartNumber = lastStartNumber + 1; return lastStartNumber; } 0 solved Give every new object a new attribute value (participants and start numbers)
I think you need: df[‘features’] = df.values.tolist() print(df) Atr1 Atr2 features 0 1 A [1, A] 1 2 B [2, B] 2 4 C [4, C] If you have multiple columns and want to select particular columns then: df = pd.DataFrame({“Atr1″:[1,2,4],”Atr2″:[‘A’,’B’,’C’],”Atr3”:[‘x’,’y’,’z’]}) print(df) Atr1 Atr2 Atr3 0 1 A x 1 2 B y 2 4 … Read more