Any server-side programming language Java for android development A strong understanding on JSON parsing Take help from Google Cloud Messaging(GCM) Tool Understanding XMPP and XMPP Server For creating an instant messaging app, you need to have knowledge on front-end development which is taken care by Android system. For storing data to servers, back-end language is … Read more
Try using the import import android.database.Cursor; instead 1 solved java.lang.NoClassDefFoundError: java.awt.Cursor
com.example.shiza.dailyquranverses.SearchResultsActivity.onCreate(SearchResultsActivity.java this line shows there is some problem with your searchactivity values which cause null pointer exception, do check with your values solved Unable to start activity from main activity which contains fragment
use following code to get screen shot from your mobile private void takeScreenshot() { Date now = new Date(); android.text.format.DateFormat.format(“yyyy-MM-dd_hh:mm:ss”, now); try { // image naming and path to include sd card appending name you choose for file String mPath = Environment.getExternalStorageDirectory().toString() + “https://stackoverflow.com/” + now + “.jpg”; // create bitmap screen capture View v1 … Read more
Activity A: pass data to activity B Intent i = new Intent(getApplicationContext,ActivityB.class); i.putExtra(“DataA”,dataA); i.startActivity(i); retrive data in ActvityB String a; Intent i = getIntent(); a= i.getStringExtra(“DataA”); pass data in actvityc from ActivityB Intent i = new Intent(getApplicationContext,ActivityC.class); i.putExtra(“DataA”,a); i.putExtra(“DataB”,b); i.startActivity(i); retrive data in ActvityC String a,b; Intent i = getIntent(); a= i.getStringExtra(“DataA”); b= i.getStringExtra(“DataB”); solved … Read more
I assume that you have maintained a map for mapping your characters with some numbers. Then you can simply split your string on empty string to get individual characters. And then iterate over your array to get the sum. Note, that, splitting on empty string will get you an empty string as first element in … Read more
Overall, using the most recent version of Android for development is the way to go. (E.g.: Pre-honeycomb versions stored raster data of images/bitmaps in native memory, thus the Memory Analyzer Tool, when you searched for memory leaks not showed the actual size of a bitmap leaked, just a few hundreds of bytes.) On the other … Read more
Facebook: You can use the Facebook API directly, since it is really easy to understand and it works great. Twitter: I suggest you to use this Twitter library, better than its API. solved Add twitter and facebook in eclipse [closed]
Write below code in onCreate() method of your activity file to get data from intent. Bundle bdl = getIntent().getExtras(); String mBankName = bdl.getString(“bank”); int mAmount = bdl.getInt(“amount”); BankName.setText(mBankName); BalanceAmount.setText(String.valueOf(mAmount)); solved Android : using same Layout for EDIT and ADD NEW – Error in ADD? [closed]
You could do some kind of xss. Depending on your website configuration if you set your cookies for all subdomains you could add a new subdomain let’s call it xss.example.com where you read the cookies and put them in GET args pointing back to an URL which is caught by your app. solved How to … Read more
You seem to have a conflict with the Android version. I couldn’t find the definitive reference but PhoneGap seems to require at least Android SDK version 7 (Android 2.1). Set the following in your manifest.xml: <uses-sdk android:minSdkVersion=”7″ android:targetSdkVersion=”17″/> You might also need to create a new emulator instance with a higher Android version. solved The … Read more
Yes, you can use HTML to create your pages, and then make your app being just single WebView object showing your pages. You put your HTML pages and related resources in res/assets folder solved How I can make a course app? [closed]
EditText fd1 = (EditText)findviewById(R.id.fd1); EditText fd2 = (EditText)findviewById(R.id.fd2); EditText fd3 = (EditText)findviewById(R.id.fd3); submitbtn.setOnClickListener(new OnClickListener() { public void onClick(View v) { String field1 = fd1.getText.toString(); String field2 = fd2.getText.toString(); String field3 = fd3.getText.toString(); dh.insert_values(field1, field2, field3); } }); On submit insert values into the database as like this.. and in your datahelper class public long insert_values(String … Read more
The fact that you have created a constructor for the Something class public Something(Activity a) { click(); } instead of using onCreate() is probably the source of the error. Something is derived from Activity, in which you have to override onCreate() at the very least, and set the View of your Activity in it. You … Read more
Try mysql_fetch_assoc: $json = array(); while ($row = mysql_fetch_assoc($result)) { $json[$row[‘uid’]] = array( ‘lat’ => $row[‘lat’], ‘lon’ => $row[‘lon’], ‘loc’ => $row[‘loc’] ); } echo json_encode($json); You should use MySQLi or PDO_MySQL instead of mysql_. 1 solved How to create json response