[Solved] Explain Output in For loop C program [closed]

the condition here is implicit.
C considers as true every integer not null.

the ++i syntax is applied before the condition is evaluated
Therefore the program run as follows:

• start:
  i=5

• first loop

condition (++i) => i=6

• second loop

iteration operation (i-=3) => i=3

condition (++i) => i=4

i is evaluated to true

• third loop

iteration operation (i-=3) => i=1

condition (++i) => i=2

i is evaluated to true

• “fourth loop”

iteration operation (i-=3) => i=-1

condition (++i) => i=0

i is evaluated to false

• end