[Solved] Compile single .java file with two classes into two .class files [closed]

Question

I am not sure what you are doing wrong so I will just show you how it can be done.

Lets say you have directories and files

[myProject]
  |
  +--[src]
  |    |
  |    +--[com]
  |        |
  |        +--[DatingService]
  |            |
  |            +-- Main.java
  |
  +--[classes]

and your Main.java file looks something like

package com.DatingService;

class c{
    private int i;
    public void setI(int i){
        this.i=i;
    }
    public int getI(){
        return this.i;
    }
}

public class Main{
    public static void main(String[] args){
        c myCVariable = new c();

        myCVariable.setI(10);
        System.out.println(myCVariable.getI());
    }
}

In terminal you need to go to myProject directory and from it use

myProject>javac -d classes src\com\DatingService\Main.java

Thanks to -d (directory) parameter packages with all compiled classes should be placed in classes directory (note that classes directory must already exist). So c.class and Main.class will be placed in myProject\classes\com\DatingService.

Now to run main method from Main class you just need to provide information about directory that contains your packages (this is ClassPath) and also use full.package.name.to.your.MainClass. So you will have to add -classpath classes (or shorter -cp classes) parameter to your java command and run it like

myProject>java -cp classes com.DatingService.Main

(note: there is no .java suffix after Main class since JVM is running binaries stored in .class files, not code from .java files)

Accepted Answer