Try like this. I have looped the items and generated the object and pushed it to class array. var data = { “Class”: [{ “StudentName”: [ “Ash”, “Win” ], “Rank”: [ “1”, “2” ], “ID”: [ “001”, “002” ] }] }; var result = {“Class”:[]} data.Class.forEach(function(details) { details.StudentName.forEach(function(det,i) { var rs = { “StudentName” : … Read more
Here you go. I acknowledge you specified a loop in your question, but in R I avoid loops wherever possible. This is better. This uses plyr::join_all to join all your data frames by Item and LC, then dplyr::mutate to do the calculations. Note you can put multiple mutations in one mutate() function: library(plyr) library(dplyr) library(tidyr) … Read more
Syntactically correcter and probably garbage.. SELECT person.CustomerID as CustomerID, address.Street as Street, (SELECT a FROM Company comp WHERE comp.Id = person.ID AND entry_key = ‘_custComment’ ) comp, (SELECT a FROM company comp WHERE company.ID = person.ID AND entry_key = ‘_otherInfo’) other from Address addr, Person person WHERE person.cid = custbasicinfo.cid AND person.cid = addr.cid solved … Read more
var regexTests = { “Needs at least 2 letters or special characters”: /(.*[A-Z!@#$%^&*()_+\-=[\]{}|;:<>?,./]){2,}/i, “Needs at least 2 digits”: /(.*\d){2,}/, “Needs at least 8 total characters”: /.{8,}/ }; function testText(txt) { return Object.keys(regexTests).filter(function(error) { return !regexTests[error].test(txt); }); } console.log(testText(“12”)); console.log(testText(“gg”)); console.log(testText(“g1”)); console.log(testText(“g11f”)); console.log(testText(“23df78sd”)); solved Javascript regular expression that matches at least 2 character (with special characters … Read more
I want to create a new Product, then add some Parts from another Document to that new ProductDoc, after two hours that seems impossible solved I want to create a new Product, then add some Parts from another Document to that new ProductDoc, after two hours that seems impossible
The same way you deal with the regular fields in class: Assumingv you have scoreStrategy and testStatistics fields: public void setScoreStrategy(IScoreStrategy iScoreStrategy) { this.scoreStrategy = scoreStrategy; } public IScoreStrategy getScoreStrategy() { return scoreStrategy; } public ITestStatistics getTestStatistics() { return testStatistics; } // … 1 solved Getters and Setters with interfaces has a parameter
This code Adds a click (event) listener to every first <td> of every <tr> On click the text is parsed to int (base10), and the number is passed to the handler function (getNumber(val)) The handler function prints the value read from the <td> to the console // “grabbing” each row const rows = document.getElementsByTagName(‘tr’) // … Read more
Assuming that your table is called df and the columns of your table are named X1, X2, X3 try the following: library(dplyr) library(tidyr) df %>% spread(X2, X3) 1 solved Conditional columns to row [duplicate]
This issue is happening because of you are using both the latest bootstrap beta version (v4.0.0-beta.3) and earlier bootstrap version (v3.3.7). I believe you have used both the following cdn path. https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0-beta.3/css/bootstrap.min.css https://maxcdn.bootstrapcdn.com/bootstrap/3.3.7/css/bootstrap.min.css If you use the above one, you will end up with the result as you showed in the image. Same you can … Read more
Always use parameterized query anyway correct your current attempt as below “INSERT INTO tbl_user (UserID, UserName, UserName , UserType) VALUES(‘” + myUser.ID + “‘,'” + myUser.Name + “‘, ‘” + myUser.Password + “‘, ‘” + myUser.Type + “‘)”; RECOMMENDED Way is to Go with parameterized query always to prevent SQL Injection Attacks SqlCommand cmd = … Read more
The $user variable isn’t an array. If that variable must not be an array remove the count function from if statement. In php5, php7.0, php7.1 it works, but in php7.2 does not work. @if($user)… 0 solved My Php Script Exception message: count(): Parameter must be an array or an object that implements Countable
Given a int suppose 5, whose binary representation is 101, we need to flip the bit which will be 010, which will be 2 [duplicate] solved Given a int suppose 5, whose binary representation is 101, we need to flip the bit which will be 010, which will be 2 [duplicate]
How is value getting retained even after function completing execution? Undefined behavior (UB). It might appear to “work”, but that is not specified to be so by C. fun(&ptr); runs fine, yet printf(“%p”,ptr); is UB as the value ptr is no longer valid. Many systems will tolerate this UB. De-referencing ptr, with printf(“%d\n”,*ptr); is even … Read more
sub $0x10,%rsp allocates space on the stack, it’s the same as doing pushq 0 twice except that the value in the allocated stack space will not necessarily be zero, but this is ok since the mov instructions used later replace the garbage with real data. As Michael rightly stated the mov $0x0,%eax is because printf … Read more
As a beginner, you should look more carefully at your code. Take it slow. Go character by character. You are missing the character “1” in your string. value = “Data: 1 Hello:Coordinator” solved String Separation at Space using python3