[ad_1] You can count the length of the string using function len. str can contain all chars and letters. Try the following code: word = input(“Waiting for input: “) print(“Found “+str(len(word))+” letters!”) Testing it: Waiting for input: hello Found 5 letters! Testing it with numbers and other chars: Waiting for input: hello123!@# Found 11 letters! … Read more
[ad_1] This is wrong with your code: dicts can only contain each key once. If you specify d1={1:1,-1:0} d2={1:2,1:1,1:0} You get dict d1 with contains keys 1 and -1 with its values and you get dict d2 wich contains only 1 as key (with value of 0 as this one was specified last). Test: d1={1:1,-1:0} … Read more
[ad_1] How about dateArray[4], seems straightforward to me. Array indexes are 0-based in Swift. You could declare a function like so: extension Array { func getElement(position: Int) -> Element { guard self.count > 0, position > 0, position <= self.count else { fatalError(“Error”) } return self[position – 1] } } And you could use it … Read more
[ad_1] Unfortunately you can’t, that’s a system message created and handled by iOS. [ad_2] solved Changing the alert title and message [closed]
[ad_1] \DB::table(‘cars’) ->join(‘garage’, ‘garage.id’, ‘=’, ‘cars.garage’) ->where(‘garage.name’, ‘main’) The above solves the garage and cars part, but you never specified what is aliased to p. If p is a different table then you need to add another call to join() and making the following \DB::table(‘cars’) ->join(‘garage’, ‘garage.id’, ‘=’, ‘cars.garage’) //<Other table join goes here for … Read more
[ad_1] Besides the error with the ( going through the code some modifications could make this a little more optimal. We can use a try, except block to eliminate the ERROR else statement and handle that directly when we receive the input if is not a valid int and we force a valid int between … Read more
[ad_1] If you have the architecture and the interfaces designed it doesn’t matter which component you implement first. So, start with those two. [ad_2] solved Where I should start coding app pc or android? [closed]
[ad_1] A simple String.replace with regex /[a-z]/ig can do! var str = “avc234jw6”; var no = parseInt(str.replace(/[a-z]/ig, “”)); console.log(no); [ad_2] solved How to remove the character form string using jQuery? [duplicate]
[ad_1] In Java 9 you have REPL which allows you to write code by typing code fragments. However, even though you don’t have to write all the code for a class the code is wrapped in a class in reality. 0 [ad_2] solved Is it possible to run java program without class?
[ad_1] This code will not compile as c# will not allow you to have methods and properties that are not defined in a class/type. Really you need to have a class and that class should have a constructor and that constructor should take a Request instance as a parameter and execute a null value check … Read more
[ad_1] When you call CreateStack, the pointer is passed by value. The pointer that is returned by the call to malloc in your function is never assigned to the STACKHEAD. Try writing a CreateStack function that returns a pointer to the stack that gets created. It should not take any arguments. 1 [ad_2] solved Data … Read more
[ad_1] # Note that variable names cannot contain hyphens flag_list = [“–syn”,”–ack”,”–push”,”–fin”,”–urg”,”–rst”] # This clearly has to be in quotes user_input = raw_input(“Enter numbers separated by comma:” ) # Split the user input string at the commas, and turn each element into an integer. flag_nums = map(int, flag_num.split(‘,’)) # List indexes start at 0, so … Read more
[ad_1] I found similar question on stackoverflow : How do I generate random numbers without rand() function? I make little modifications for generating between 0-35 and final solution: #include<stdio.h> #include<time.h> int main() { int num = 36; time_t sec; sec=time(NULL); for(;;) { sec=sec%3600; if(num>=sec) { printf(“%ld\n”,sec); break; } sec=sec%num; } return 0; } Here we … Read more
[ad_1] The error message is pretty clear: The type ‘Edm.String’ of member ‘SEJ_STARDATE’ in type ‘HotelSearch.APP_SEJOUR’ is not compatible with ‘SqlServer.date Change edm.String to a recognizable datetime format (MM/DD/YYYY) by manipulating its contents or using DateTime.Parse [ad_2] solved “Member Mapping specified is not valid” error when saving to a database with Entity Framework
[ad_1] Use regexp: $x = preg_match_all(“/\\w{6,}/”, “Elephant shoe penguin food telephone”, $matches); [ad_2] solved PHP, I want to count the number of words in a string with more than six letters