The code you provided does not work on any numbers. The only thing it does is construct some SQL query check its result During the SQL-query-construction, the code does not assume any “numbers” to be provided. It actually uses a variable called password_txt->Text, which suggests it’s some form of TextBox control. The code gets the … Read more
You should elaborate what you want? Do you want a popup or an arrow like one shown in the screenshot? Try this: http://jsfiddle.net/F47uy/ CSS: #arrow{ border-left: 15px dashed transparent; border-right: 15px dashed transparent; border-bottom: 15px dashed grey; margin-left:200px; width:0; height:0; } #box{ background:grey; width:300px; height:300px; } solved Make a div like google [closed]
First, you need to make a loop. The loop needs to execute a number of times equal to the length of the input string minus the length of the substring you want to evaluate. Calculate that length before constructing the loop. $digits = 5; $count = strlen($number) – $digits; Then initialize a maximum value. Loop … Read more
The following array formula returns the first entry in column B where it is not null and also where column A has cell value aaaaa. = IFERROR(INDEX(B1:B6,MATCH(1,(A1:A6=”aaaaa”)*(B1:B6<>”null”),0)),”no match”) Note this is an array formula, so you must press Ctrl+Shift+Enter on the keyboard after typing the formula rather than just pressing Enter. To return a similar … Read more
new is for dynamic allocation (of an array on the heap in this case), and returns a pointer to the new array. [] in the declaration are for declaring it to be a stack array (and the brackets belong the right side of the variable name). So the two legal approaches your code is mixing … Read more
read.table returns a data frame (as per the documentation), which is not the same thing as a matrix. As I’m sure you’re aware, your data had three columns, only the second two being numeric. When you convert the data frame from read.table to a matrix with as.matrix R coerces everything to a single type. This … Read more
So let’s go over this piece by piece. The $ is usually a reference to jQuery (https://jquery.com/) which is a library of a lot of really useful JavaScript functions and things. $(document) This is what’s known as a jQuery selector. Essentially it locates whatever you put into it, and wraps it in a jQuery object … Read more
Why are you using onclick? onclick executes javascript code. Just link to the file <a href=”https://stackoverflow.com/questions/12374789/myscript.php”>Say Hello</a> If you must use javascript, you have to redirect to that page using something like window.location Here’s a tutorial on redirecting with javascript solved Launch a php script without form
The first class is static, which means: You can’t use it as a type argument You can’t use it as a variable type It will have no instance constructors (whereas your non-static class implicitly has a public parameterless constructor) It will be implicitly abstract and sealed (even though that combination can’t be static It cannot … Read more
You are passing a pointer to a local variable. Once your function ends, this variable is gone. If this is C++ you should use the string class. If for whatever reason you don’t, at least be const correct: const char* Worker::getName() const { return name; } 1 solved cout corrupt char* [closed]
In all versions of C++, the second version (Foo::States::BAR) using scope syntax is the more conventional and will be less surprising for future maintainers of your code. Since the value is a constant, there is no need for an instance of the class, so this is similar to how static methods are most often called … Read more
The assignment expression x = n evaluates to the value assigned to x. So a = 4 evaluates to 4, and b = 0 evaluates to 0. In C and C++, non-zero values are true, and zero values are false. 3 solved Why is a=4 evaluated as true but b=0 evaluated as false in an … Read more
You can use : $this->db->get_where(‘product’, ‘category_id >=10’); OR $this->db->where(‘category_id >=10’); 0 solved how to get result form mysql query in specific ids [closed]
you’re comparing string and char type replace where r1[4] == “I” / where r1[4] == “O” with where r1[4] == ‘I’ / where r1[4] == ‘O’ 3 solved LINQ Operator ‘==’ cannot be applied to operands of type ‘char’ and ‘string’
ex.message.Contains(“Cannot open server”) && ex.message.Contains(“requested by the login”) solved How can I check if a string contains two other strings [closed]