[Solved] Limit output to 5 items [duplicate]
you can use the head command to limit the output of grep to the first 5 results before passing it to xargs. Here’s the modified command: grep -r -l ‘foo’ | head -n 5 | xargs sed -i ‘s/foo/bar/g’ For…
you can use the head command to limit the output of grep to the first 5 results before passing it to xargs. Here’s the modified command: grep -r -l ‘foo’ | head -n 5 | xargs sed -i ‘s/foo/bar/g’ For…
fopen, calloc, and realloc can all fail, returning NULL. In the case of realloc, the original allocation will remain untouched, so immediately overwriting the original pointer with the newly returned value will leak memory and throw away potentially useful data.…
Your code exhibits undefined behaviour because you passed a non-static, uninitialised pointer to realloc whose contents were indeterminate. From C11, Memory Management Functions: The realloc function deallocates the old object pointed to by ptr and returns a pointer to a…
When processing regular characters (final else clause) you read additional input instead of operating over text, i.e. instead of: scanf(“%c”, &document[parano][sentno][wordno][charno]); printf(“%c\n”, document[parano][sentno][wordno][charno]); charno++; you want to do: document[parano][sentno][wordno][charno++] = text[i]; By the time we hit text[i] == ‘ ‘…
Introduction If you’ve been struggling with a document for two days and can’t seem to get it to work, you’re not alone. Many people have difficulty understanding the complexities of document formatting and troubleshooting. Fortunately, there are many resources available…
You want to modify the value of an int* (your array) so need to pass a pointer to it into your increase function: void increase(int** data) { *data = realloc(*data, 5 * sizeof int); } Calling code would then look…
Invalid assumption: void *my_realloc(void *ptr, size_t size) { unsigned char *old_ptr = (unsigned char *)ptr; You’re breaking the realloc() specification here. realloc() doesn’t assume that the ptr would always be pointing to a string. It is type-agnostic. And the cast…
OP’s mostly has it. It is just printing the first element each time. // printf(“%d”, *arr); printf(“%d”, arr[n-1]); is it possible to do it with an array? No. In C an array cannot change size once it is defined. The…
What you’re doing will work. Each time you increment contents, you also increment counter, so contents – counter gives you the original pointer that you can free. Of course, a better way of doing this would be to use a…
This answer is based on the assumption that you do proper handling of your pointers between the part where you allocate memory for 1 element each and where you try to reallocate the memory. This part // realloc to correct…
It is always easier to divide program into logical bits and place them in functions. char *addToBuff(char *buff, int ch, size_t *size) { //working on local variable buff. No need for a temporary variable buff = realloc(buff, *size + 1);…
You should reduce the number of columsn, not rows. Not mat1 but mat1->array should be reallocated. Not nrow and ncol (not updated) but mat1->nrows and mat1->ncols (updated) should be used for the new size. The elements are size_t, so allocating…
At least this statement array->values = realloc(array->values, array->capacity); shall be rewritten like array->values = realloc(array->values, array->capacity * sizeof( Value ) ); Though it would be more safer to use an intermediate pointer like for example Value *tmp = realloc(array->values, array->capacity…
In your function int huffman(node_t *huff, int n) you try to realloc() the huff pointer but in C we pass variables by value so you only receive a copy of the pointer. This means caller retains the original pointer and…
The function is not updating the caller’s value of client_details, you need one more level of pointer: void func(struct client_detail **client_details,int *size){ *client_details = realloc(*client_details, (*size + 1) * sizeof(**client_details)); *size = *size + 1; } int main() { struct…