[ad_1] Your for(var j=0; j < accentArray.length; j++) is meaningless. You are not using the j variable anywhere. You just make the inner codes run accentArray.length times. If you want to check if the string includes an accent, you could write if ([…str].some(c => accentArray.includes(c))) There is a better way to remove characters from a … Read more
[ad_1] Compare X ≡ s1 * m2 with Y ≡ s2 * m1. If X > Y, then s1 / m1 > s2 / m2. No division is required to do the comparison. The caveat to this solution is that s1, s2, m1, and m2 should all have the same sign, and m1 and m2 … Read more
[ad_1] Now that you have mentioned lat-long (missing in the question description), see this http://www.scribd.com/doc/2569355/Geo-Distance-Search-with-MySQL [ad_2] solved A simple bus reservation system [closed]
[ad_1] Let’s start from the middle of this expression. ‘3’ * 2 evaluates to ’33’. This is because multiplication of a str object by a int object results in concatenating string with itself n times (providing you are multiplying by n). int(’33’) is just 33 as an integer. When you feed int class a string … Read more
[ad_1] You can do in following way: a.sort { return $0.last as! Int > $1.last as! Int } Don’t forget to add additional checks while using this code, case where the last item is not an integer or there is an array not in the expected format. Otherwise, it will lead to a crash. 0 … Read more
[ad_1] Well I just visit your side, You can do one thing in that. I have noticed there are many CSS and JS files used in your site. But many of them in their actual version. You can minify all CSS and JS file’s code with Laravel’s Mix Feature This will convert the whole code … Read more
[ad_1] You can use collection, map or each for this data = {a: [1,2,3,4,5,6,7,8,9],b: [1,2,3,4,5,6],c: [2,3,4,5,6,7]} data.map{|k,v| (1..9).map{|a| data[k].include?(a) ? k.to_s.upcase() +a.to_s : ‘ ‘}} 9 [ad_2] solved Ruby Program to print pattern [closed]
[ad_1] Try this, I tested it and it works, you should use the remainder operator %: public class Array { public static void main(String[] args) { int[] arr = {2, 3, 5, 7, 11}; System.out.println(is235Array(arr)); } public static int is235Array(int[] a) { int countOne = 0; int countTwo = 0; for (int i : a) … Read more
[ad_1] You can use selectionEnd to control the position of cursor var target = document.querySelector(‘.creditCardText’); target.addEventListener(“keyup”, function() { var position = target.selectionStart; var prevVal = target.value; var newVal = prevVal.split(” “).join(“”); // remove spaces if (newVal.length > 0) { newVal = newVal.match(new RegExp(‘.{1,4}’, ‘g’)).join(” “); } target.value = newVal; for (var i = 0; i … Read more
[ad_1] For WordPress, you would need to know basic PHP, and also how wordpress works. For this, I suggest reading Writing a plugin for WordPress For the scratch card, you can make this in CSS and JS. For an example, I refer you to Canvas – Scratch Card ´ 1 [ad_2] solved How to get … Read more
[ad_1] Your logic of result*=devided; is wrong. You need to add the digit(multiplied by it’s 10’s place) to the result. Here is the solution to your problem. int function (int *n, int i){ int temp=n[i]; //tepmorary veraible of the passed number int result=0; int mult=1; int devided; while (temp!=0){ devided=temp%10;//get the last number example 123 … Read more
[ad_1] In javascript you can try to use this regexp /\+91[0-9]{10}/ 1 [ad_2] solved Regexp for all Indian phone numbers in 2018 [closed]
[ad_1] after converting to datetime pd.to_datetime(df[‘date’]) you can create a separate column with the hour in it, e.g. df[‘Hour’] = df.date.dt.hour and then sort by it df.sort_values(‘Hour’) EDIT: As you want to sort by time you can instead of using hour, put the timestamp part into a ‘time’ column. In order to get times between … Read more
[ad_1] We can see this problem as an instance XOR-SAT problem, though it is more general than the problem posed here, that’s one way to go. Just to gain some intuition I provide a very simple example. Suppose you have systems of three switches and three bulbs like this: S B 1 1, 3 // … Read more
[ad_1] Javascript has a built in atob and btoa function. <script type=”text/javascript”> function doAtob() { var val = document.getElementById(“inputbox”).value; var out = document.getElementById(“outval”); out.appendChild(document.createTextNode(atob(val))); } </script> <input id=”inputbox” type=textbox /> <button onclick=’doAtob()’>Do it!</button> <span id=”outval” /> [ad_2] solved How Do I Execute btoa(string); using HTML and JS