[Solved] Android NetworkOnMainThreadException [duplicate]

[ad_1] You are not allowed to do network operations with the Main (UI) thread. There are several ways of using background threads. I would recommend using AsyncTask since it has a nice structure which is easy to understand. http://developer.android.com/reference/android/os/AsyncTask.html Here is an SO example also: AsyncTask Android example Should be a lot more available on … Read more

[Solved] How to refactor my conditional statement? [closed]

[ad_1] A ternary that reproduces your if/else: title = title == ‘project’ ? text + ‘: ‘ + this.projectTitle : this.projectTitle; Though if you really want to shorten it: title = (title == ‘project’ ? text + ‘: ‘ : ”) + this.projectTitle; References: Conditional (‘ternary’) operator. [ad_2] solved How to refactor my conditional statement? … Read more

[Solved] Button not doing anything on click. How come? [duplicate]

[ad_1] Your strings are quoted wrong, your second double quote after on click = terminates the string, I havent tested my soloution but you need something like (below) You need to escape double qoutes if it is literally part of the string echo “<tr><td colspan =’2′><center><input type=”submit” value=”Reply” onClick=’window.open(\”post_reply.php?cid=$cid&tid=$tid\”)’ />”; 0 [ad_2] solved Button not … Read more

[Solved] What is the best way to have only single database connection throughout whole android app life?

[ad_1] THere is no way, not how you’re doing it. You’re making individual HTTP connections for each request. Unless your webserver only maintains a single instance of a database connection for all requests, its going to create new ones for each request (this would also mean your website only has a single server- in other … Read more

[Solved] switch a Button and Get a different at the Bottom

[ad_1] Create a new Fragment that describes what you want to do in each pane. For example, import android.app.Fragment; import android.os.Bundle; import android.view.LayoutInflater; import android.view.View; import android.view.ViewGroup; public class ButtonOneFragment extends Fragment { public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) { if (container != null) { container.removeAllViews(); } return inflater.inflate(R.layout.button_one_fragment, container, false); } public … Read more

[Solved] Survival analysis [closed]

[ad_1] This should solve your problem: mod <- survreg((Surv(as.numeric(Time), event=Status)) ~ Prison+Dose+Clinic, data = meth, dist = “lognormal”) as you reported to me that: names(meth) # [1] “ID” “Clinic” “Status” “Time” “Prison” “Dose” Note, it is Time, not time; Also, it is Status, not status. In fact, all variables names start with a capital letter! … Read more

[Solved] Associative array index as variable

[ad_1] Try foreach ($array1 as $index => $arr1) {…} foreach ($array1 as $key1 => $val1 ) { foreach ($array2 as $key2 => $val2) { echo $arr2[$arr2[$key1][$key2]]; } } 0 [ad_2] solved Associative array index as variable

[Solved] How to add a row to non-unique table class using jquery

[ad_1] Try to use the filter() function. $(‘table.yourclass’).filter(‘:first’) // first of matched tables $(‘table.yourclass’).filter(‘:last’) // last of matched tables $(‘table.yourclass’).filter(‘:eq(2)’) // 3rd matched table http://api.jquery.com/filter/ 1 [ad_2] solved How to add a row to non-unique table class using jquery

[Solved] jQuery if element is visible, what am I doing wrong?

[ad_1] You don’t need that if at all; and you are not using it right as described in the answer of @SLaks. Why won’t you assign functions to an invisible element? I guess we should do that, so I think this is what you want: http://jsfiddle.net/balintbako/yuAhb/1/ $(‘button.nav-mobile-switch’).click(function () { $(this).hide(); $(‘ul.site-nav.actual-navigation’).show(); return false; }); $(document).click(function … Read more

[Solved] How to use non-online images in CSS?

[ad_1] If, for example, your image is in the directory images/image.png, relative to the HTML file You would use <img src=”https://stackoverflow.com/questions/17406396/images/image.png” />. This will work both online and locally. 0 [ad_2] solved How to use non-online images in CSS?

[Solved] Iteration of an integer

[ad_1] You could just use simple math in Java. Example: int peopleAmount = 3; int money = peopleAmount * 5; System.out.println(money); //Would print 15 This example would calculate the money I would need if I give 3 people each 5$. You can easily adapt that example. I know it can be hard to learn a … Read more

[Solved] Range of linked lists [closed]

[ad_1] Your linked list declaration is wrong. You don’t use [] when creating a new object in java. Instead you use (). And your generic type is also wrong -> if you want to have more linked lists inside the main linked list. Try this LinkedList<LinkedList> LK = new LinkedList<>(); Note – The part inside … Read more