[Solved] C# I/O vs C I/O

[ad_1] There is probably not a significant performance gain in using a C/C++ dll. The C# runs in an environment with a quite efficient JIT compiler, so my guess is that the code performance is limited by a hard disk read speed of approximately 100 MB/s. Of course, if you have an SSD, your mileage … Read more

[Solved] How can get two collection documents and calculate points using express.js?

[ad_1] exports.show = = function(req, res) { var userdata = [{ “productcode”: “9563456789”, “cost”: “1000” }, { “productcode”: “8756348947”, “cost”: “5600” }] var parameterObject = []; Parameter.find().exec(function(err, Parameters) { if (err) { return handleError(res, err); } // i want to push Parameters[0].value to parameterObject parameterObject.push({ pointvalue: Parameters[0].value }); return FindProducts(parameterObject, function(data) { console.log(data); }); }); … Read more

[Solved] How do I achieve a bubbleplot? [closed]

[ad_1] To achieve this you could use ggplot. Here an example: require(ggplot2) df <- data.frame(x = c(-2, -1.5, 1, 2, 3), y = c(-1, 0.8, 1, 1, 2), country = c(“SWI”, “FRA”, “US”, “UK”, “NL”), size = c(15,12,20,4,7)) ggplot(df, aes(x = x, y = y)) + geom_point(aes(size = size), pch=1) +geom_text(aes(label=country),hjust=-0.5, vjust=0) + xlim(c(-3,4)) + … Read more

[Solved] Two streams and one file

[ad_1] It depends on your operating system. On Windows the new FileOutputStream(…) will probably fail. On Unix-line systems you will get a new file while the old one continues to be readable. However your copy loop is invalid. available() is not a test for end of stream, and it’s not much use for other purposes … Read more

[Solved] Can’t Find Seg Fault in C Code

[ad_1] Valgrind and GDB are very useful. The most previous one that I used was GDB- I like it because it showed me the exact line number that the Segmentation Fault was on. Here are some resources that can guide you on using GDB: GDB Tutorial 1 GDB Tutorial 2 If you still cannot figure … Read more

[Solved] Cannot change anchor text font size when it is inside a div

[ad_1] You forgot to add the unit of measurement to the font-size. Add px, em, or % to the end of 18. .linkunderthepicture a { width: 99%; font-size: 48px; text-decoration: underline; font-weight:bold; text-align: center; } <div class=”linkunderthepicture”><a href=”http://google.com”>Click</a></div> [ad_2] solved Cannot change anchor text font size when it is inside a div

[Solved] opening Internet Explorer using c programming language

[ad_1] I guess you have specified the path to Internet Explorer like this “C:\Program Files\Internet Explorer\iexplore.exe” But because the \ character is an “escape” character in a literal string, you need to defeat the escape “C:\\Program Files\\Internet Explorer\\iexplore.exe” There was no error when you compiled because the compiler cannot check whether the command passed to … Read more

[Solved] java.lang.NullPointerException while fetching value from EditText [duplicate]

[ad_1] You can’t just instantiate your Activity and access the TextView members on it. This doesn’t make any sense: indoor_patient ins=new indoor_patient(); String webUrl = “http://10.0.3.2:8084/data_web/indoorPatient.jsp?sr_no=” + ins.sr_no.getText().toString() Instead you could figure out what your webUrl is in your onClick() method and pass in the complete URL as a parameter to the AsyncTask: submit.setOnClickListener(new View.OnClickListener() … Read more

[Solved] Recheck the URL thrice for web exception cases powershell

[ad_1] You are looking for something like this ? #Remove-Variable * -ErrorAction SilentlyContinue $url = “www.yourtargetsite.com” function try-webrequest($url){ try{ return (Invoke-WebRequest -uri $url -ErrorAction Stop) }catch{ return $_ } } $wr = try-webrequest $url if ($wr.statuscode -ne 200){ If($wr.categoryinfo.reason -eq “webexception”){ $count = 1 while($count -lt 4){ “Retrying…$count” $count++ if ((try-webrequest $url).statuscode -eq 200){break} sleep … Read more

[Solved] Letter combinations of a phone number

[ad_1] The problem is that you’re both looping and recursing. print(“22”, “”, 0); will recurse into print(“22”, “a”, 1); print(“22”, “b”, 1); print(“22”, “c”, 1); print(“22”, “a”, 2); print(“22”, “b”, 2); print(“22”, “c”, 2); and your extra bits are the last three calls. Get rid of the loop over the input digits (you’re already doing … Read more