Kirat[ad_1] I think you need empty list so you can append the numbers to that i.e FirstNumbers = [1, 2, 3] SecondNumbers = [4, 5, 6] ThirdNumbers = [7, 8, 9] NestedNumbers = [FirstNumbers, SecondNumbers, ThirdNumbers] m = [] for i in range(0, 3): k = [] for each_number in NestedNumbers: k.append(each_number[i]) m.append(k) Output m … Read more
[ad_1] Your code should be : #include <stdio.h> int main() { int r,sales; printf(“Enter sales in dollars : “); scanf(” %d”, &sales); r = sales * 9 / 100+200; printf(“Salary is %d”, r); return 0; } You must first get the value of sales before adding it to a formula. 5 [ad_2] solved why is … Read more
[ad_1] It’s typically an inflation error. You would need to compare the View IDs that you are attempting to populate, make sure they are not null and that you are setup with your Recycler View Holder Adapter properly. Post your adapter, your xml for the row that you are filling, your viewholder pattern and your … Read more
[ad_1] Split the string into array: String x = “What is my name”; String[] splitted = x.split(” “); for (int i = 0; i < Array.getLength(splitted); i++) { System.out.println(“Word ” + (i+1) + “: ” + splitted[i]); } You can change System.out.println() to your desired output method. Edit (as suggested in comment): For safer code, … Read more
[ad_1] Let’s say the time zone offsets are valid, they are in hours and minutes always separated by a colon (‘:’) and preceded by a ‘+’ or ‘-‘. So var utcOffset = “+05:30”; var a = uctOffset.split(‘:’); var hour = +a[0]; var minute = +a[1]; What you do with the hour and minute values is … Read more
[ad_1] Looks like you’re trying to do something like this: static String HTMLchange(String src) { return src.replaceAll(“ber”, “vai”); } which replaces every occurrence of “ber” in the string with “vai” UPDATE using in.next() fetches the next token. Whitespace is considered as a legit delimiter so when the user enters the string “x ber x” the … Read more
[ad_1] If you have 1920 pixels numbered from 0, the max will be 1919. If the coordinate was 1920, then you’d be looking at 1921st pixel. 0 is the first pixel, 1 is the second pixel 1919 is the one thousand nine hundred and twentieth pixel [ad_2] solved How to get the missing pixel in … Read more
[ad_1] the rationale is to set the internal pages as Partial View, and from the container page (Layout) bring the Map1, Map2, About, Contacts with Ajax in javascript: View (layout, but not just): <div id=”DestinationLayoutDiv”> </div> Javascript: $.ajax({ url: ‘@Url.Action(“action”, “controller”)’, data: { _param: param}, type: ‘GET’, success: function (data) { $(‘#DestinationLayoutDiv’).html(data); } }); Controller: … Read more
[ad_1] One wrong thing in your check function: you only check the names in the current team to skip that, but you should skip any name that was already put in a team. I already gave you an alternative on another question, so the check function isn’t needed (erasing from the list). Also, when iterating … Read more
[ad_1] Let’s say you have 2 tables: ID Name 1 Smith 2 Novak 3 Tarantino and the second table ID Cash 2 300 3 490 4 500 INNER JOIN will join records that have match in both tables, i.e. in the result table only ID 2 and 3 will be included, because they have match. … Read more
[ad_1] The query below uses a Join which should be faster than a subquery. Select t1.ContractId, t2.MissionId From tab t1 Join tab t2 ON t1.ContractId = t2.ContractId Group By t1.ContractId, t2.MissionId Having Count(*) > 1 2 [ad_2] solved Sql request selection
[ad_1] You can use the following query: SELECT cust_name FROM mytable GROUP BY cust_name HAVING COUNT(*) > 1 to get the cust_name values of duplicate records. Use this query as a derived table and join back to the original table to get the desired result: SELECT t1.* FROM mytable AS t1 JOIN ( SELECT cust_name … Read more
[ad_1] Well you question is divided into 2 parts and I’ll answer them both. 1- What you are looking for is UIGestureRecognizer where it’ll recognize a gesture and do an action accordingly. Here is a link taht will help you out! https://www.raywenderlich.com/76020/using-uigesturerecognizer-with-swift-tutorial 2- Unlocking the phone is impossible without jailbreak. Your gestures are bound to … Read more
[ad_1] You can do with a count variable, e.g.: public static void main(String[] args) throws Exception{ int i; int count = 1; for (i=1;i<=100;i++) { System.out.print(i); if(count % 5 == 0) { System.out.print(“*”); }else if(count % 8 == 0) { System.out.print(“*”); count = 0; } count++; } } 3 [ad_2] solved Print asterisk after some … Read more
[ad_1] This is a bug that will be fixed in an upcoming release. To resolve this, change your Version to a version that is > API 19. https://bugzilla.xamarin.com/show_bug.cgi?id=56272 Otherwise upgrade to 15.3 in your Visual Studio Installer to receive this fix as it is included in Xamarin.Android 7.3.0.27 and above. [ad_2] solved Downgrade the android … Read more