[Solved] Computing the overtimepay is my formula correct?

[ad_1] Your calculation is alright (not that complicated after all!), I’d just suggest to change your condition statement to reduce a bit your code: double hours, overtimepay, wage; printf(“Enter number of hours: “) scanf(“%f”,&hours); wage=9.73*hours; wage = 9.73 * hours; printf(“Your wage is: %f\n”,wage); if(hours > 40) { overtimepay = (9.73*(hours-40))*1.5; printf(“Your overtime pay is: … Read more

[Solved] Java to python conversion [closed]

[ad_1] If you are iterating over the items in some container, just iterate over that container; don’t use the index unless you need to. Right: slots = [1, 2, 3, 7] for slot in slots: print cards[slot] Wrong (or at least “writing C/C++/Java/C#/whatever in Python”): slots = [1, 2, 3, 7] for i in range(len(slots)): … Read more

[Solved] missing binary operator before token “(“

[ad_1] You misspelled defined: #if definied(_WIN32) || definied(_WIN64) || definied(__WIN32__) #elif definied(__linux) || definied(__linux__) || definied(linux) should be: #if defined(_WIN32) || defined(_WIN64) || defined(__WIN32__) #elif defined(__linux) || defined(__linux__) || defined(linux) [ad_2] solved missing binary operator before token “(”

[Solved] Code throws warning: Undefined index in GET array [duplicate]

[ad_1] Its because if the ?page paramater isn’t set in the URL it will throw that error. Replace with the following code: $page = (isset($_GET[‘page’])) ? $_GET[‘page’] : ”; // gets the variable $page ****** //global $page; if (!empty($page)){ include($page); } // if $page has a value, include it else { include(“home.php”); } // otherwise, … Read more

[Solved] input in C programming language

[ad_1] The value have only 2 decimal places is a matter of displaying it, so you just need to print the number of decimal places you are interested in, like float value = 123.123456; printf(“%.2f\n”, value); if you want to dynamicaly specify that number, you can use float value = 123.123456; int decimals = 2; … Read more

[Solved] Ruby regex method

[ad_1] Use regex /r\d+=\d+/: “http://test.com?t&r12=1&r122=1&r1=1&r124=1”.scan(/r\d+=\d+/) # => [“r12=1”, “r122=1”, “r1=1”, “r124=1”] “http://test.com?t&r12=1&r124=1”.scan(/r\d+=\d+/) # => [“r12=1”, “r124=1”] You can use join to get a string output. Here: “http://test.com?t&r12=1&r122=1&r1=1&r124=1”.scan(/r\d+=\d+/).join(‘,’) # => “r12=1,r122=1,r1=1,r124=1” Update If the URL contains other parameters that may include r in end, the regex can be made stricter: a = [] “http://test.com?r1=2&r12=1&r122=1&r1=1&r124=1&ar1=2&tr2=3&xy4=5”.scan(/(&|\?)(r+\d+=\d+)/) {|x,y| a … Read more

[Solved] How do this with only CSS

[ad_1] Using a solid background? If you are using a solid colour background, you could use a pseudo element to ‘cover it up’ .wrap { position: relative; height: 300px; width: 300px; } .img { height: inherit; width: inherit; background: url(http://lorempixel.com/300/300); position: relative; overflow: hidden; z-index: -2; } .img:before { content: “”; position: absolute; top: 100%; … Read more

[Solved] Does there exist an algorithm for iterating through all strings that conform to a particular regex?

[ad_1] Let’s say the domain is as following String domain[] = { a, b, .., z, A, B, .. Z, 0, 1, 2, .. 9 }; Let’s say the password size is 8 ArrayList allCombinations = getAllPossibleStrings2(domain,8); This is going to generate SIZE(domain) * LENGTH number of combinations, which is in this example (26+26+10)^8 = … Read more

[Solved] Parentheses Reduction

[ad_1] As correctly stated in Turing85’s comment, you can actually remove every parenthesis except the outer ones if (weight < 160 && age <= 27 && age >= 22 && height < 72 && !isASmoker && isMale && isGoodLooking && isAbleToRelocate ) this is the minimum number of parethesis you can use. The maximum number … Read more