[Solved] can’t understand where is syntax error [closed]

[ad_1] 1) scanf(“%s”,input) and not scanf(“%s”,&input) input holds the address of the array. &input passes the address of input. 2) Syntax of for loop is: for ( init; condition; increment ) { //code } Hence the for loop should be: for(i=0,j=c-1;i<=j && j>=0;i++,j–) 6 [ad_2] solved can’t understand where is syntax error [closed]

[Solved] GetOption PERL to Python

[ad_1] There is a module in python called argparse. You can use the module to solve your problem. Code example : test.py import argparse import os commandLineArgumentParser = argparse.ArgumentParser() commandLineArgumentParser.add_argument(“-fname”, “–fname”, help=”first name”) commandLineArgumentParser.add_argument(“-lname”,”–lname”, help=”last name”) commandLineArguments = commandLineArgumentParser.parse_args() fname = commandLineArguments.fname lname = commandLineArguments.lname print “%s\n%s” %(fname,lname) Run example python test.py -fname ms -lname … Read more

[Solved] Issue with my website url [closed]

[ad_1] You need to move the home.html file in to the start directory, in other words not in any folders or just out of the OBI1.0 folder, and rename it index.html. Then you can go to obiventures.com / http://obiventures.com / http://obiventures.com/ and it will be there. Oh, and nice website by the way. 0 [ad_2] … Read more

[Solved] Convert JSON string to data array using javascript or c# [closed]

[ad_1] Example JSON String string data = “{ \”A\” : \”1\”, \”B\” : \”2\”, \”C\” : \”3\” }”; Deserializing it into an object that will contain each of the keys and their values object yourObject = new JavaScriptSerializer().DeserializeObject(data); 1 [ad_2] solved Convert JSON string to data array using javascript or c# [closed]

[Solved] use html button to call javascript function [closed]

[ad_1] I don’t fully understand your question, but I’m guessing you want your solve() function to execute when a button is pressed. Here are three options: window.onload = function() { var button = document.getElementById(“button”); // Method 1 button.addEventListener(“click”, function() { alert(“clicked1”); solve(a, b, c); // ^ Insert Params ^ }); // Method 2 button.onclick = … Read more

[Solved] how do I configure email on a contact form?

[ad_1] Seding an email directly with javascript (as it´s your tag) is not possible, but you can open the user mail client: window.open(‘mailto:[email protected]’); It´s possible to have a predetermined subject and body using these variables: window.open(‘mailto:[email protected]?subject=example_subject&body=example_body’); 3 [ad_2] solved how do I configure email on a contact form?

[Solved] I have an array of strings. I want to print those that start with the word New.

[ad_1] input_arr = [ “New: Hello”, “How are”, “you”, “New: I am”, “fine” ] def merge_messages(input_arr): delimiter = “New” return [delimiter+x for x in ” “.join(input_arr).split(delimiter) if x] print(merge_messages(input_arr)) However, I would highly recommend you take the advice given to you in the comments and read up on Python Strings. You can also view the … Read more

[Solved] Using getchar() to Read Two Strings

[ad_1] You need to add string terminators ‘\0’ to your string before printing (or zero out the buffers memory first). Also: you have declared buffers of size 20, but have no guards in your code to respect that allocated length, which means you could overrun them and corrupt memory. [Run with two words greater than … Read more

[Solved] How is a for loop written in Perl?

[ad_1] There are two types of for loop in perl, in addition to the for statement modifier. They look like this: # c-style for loop for ( my $i = 0; $i < 12; ++$i ) { … } # regular for loop for my $i (0..11) { … } # statement modifier … for … Read more

[Solved] What will be the algorithm to solve the given series?

[ad_1] try to separate the coefficients from polynomials and calculate those in separate methods. Example: public class NewClass { public static void main(String[] args) { int greatestExponent = 9; double x = 0.5; System.out.println(calculate(x,greatestExponent)); } public static double getCoefficient(int n){ double coff = 1; for(int i=1; i<n; i++){ if(i%2==0){ coff = coff/i; //if even put … Read more