Add a timer control to your application. Subscribe to mouseover and keydown events – when they fire, reset the timer. When the timer fires (ie mouse hasn’t moved and key’s haven’t been pressed for x amount of time), lock the screen / prompt for login. This could also help: http://www.codeproject.com/Articles/13756/Detecting-Application-Idleness solved How to check if … Read more
lets analyze a few of the the possible error messages: java.lang.OutOfMemoryError: Java heap space java.lang.OutOfMemoryError: PermGen space java.lang.OutOfMemoryError: Requested array size exceeds VM limit java.lang.OutOfMemoryError: request <size> bytes for <reason>. Out of swap space? java.lang.OutOfMemoryError: <reason> <stack trace> (Native method) Here’s the MemLeak class: package com.post.memory.leak; import java.util.Map; public class MemLeak { public final String … Read more
Ok, i figured it out. Thanks @TartanLlama for the last comment it makes total sense. So the “core error” (the thing that i wanted to know) was in here: float /* */ soma_transmissor, soma_recetor; for(i=0;i<n;i++){ soma_transmissor+=distobj[i]; /* */ } for(i=n-1,k=n;i>=0;i–){ soma_recetor+=distobj[i+1]; /* */ } I just needed to inicialize soma_transmissor and soma_recetor. Now if anyone … Read more
You might want to check your while condition! Since the conditions are in the negation, you would use AND ( && ) instead of OR (||) to combine them. EDIT: And as pointed out, you ought to be comparing Die1 and Die2 to numbers. If you’d like to keep the characters as is, you could … Read more
Using the marquee tag is not standard. https://developer.mozilla.org/en-US/docs/Web/HTML/Element/marquee Also I would avoid to wrap a div with a p tag as it’s semantically not correct and are supposed to contain only inline elements. I would separate the styling from the div tag. and do something like this: https://jsfiddle.net/Mehdikit/bs9shwt0/ HTML & CSS .container { position: relative; … Read more
If you want to get the uppercase of a char, you should use Character.toUpperCase(c), not String’s toUpperCase. So, I think you might be looking for something like this: public static void main(String[] args) { String alphabet = “abcdefghijklmnopqrstuvwxyzåäö”; System.out.println(alphabet); StringBuilder sb = new StringBuilder(); for (int i = 0; i < alphabet.length(); i++) { char … Read more
No it matters. Pointer arithmetic solely depends on what it points to. For example int(*p)[2] and int *p both of them are different. The same way int **p and int ***p is different. You might think even if the sizeof (int*) and sizeof(int**) is same – it is not logical to lose the multiple indirection … Read more
You declared: int FLIP_RESULT = rand() % 2 + 1; at the start of your code. This means that the flip happens only once at the start of the program, regardless of the number of flips the user inputs. Try randoming the FLIP_RESULT as first line of your for loop, and you’ll see it working. … Read more
Use a loop and an ExecutorService. ExecutorService executor = Executors.newCachedThreadPool(); for (int i = 0; i < count; i++) { executor.execute(new TokenStarter()); } That should recreate your code, but is not optimal. You probably want to limit the amount of threads that run concurrently: ExecutorService executor = Executors.newFixedThreadPool(desiredParallelism); solved Optimizing thread calls in Java [closed]
// will match http://localhost only: $(‘a[href=”http://localhost”]’).find(‘img’).attr(‘alt’); // will match links hreffing to URLs starting with http://localhost $(‘a[href^=”http://localhost”]’).find(‘img’).attr(‘alt’); 6 solved Get img alt which parent a’s href is something [closed]
Group the rows by date, use COUNT(*) to get the count of rows in each group, and then use ORDER BY and LIMIT to get the highest count. SELECT DATE(timestampColumn) AS date, COUNT(*) AS count FROM yourTable GROUP BY date ORDER BY count DESC LIMIT 1 9 solved How to get the count of day … Read more
The .0 in somePoint.0 is accessing the first element (at index 0) of the tuple somePoint. .1 is accessing the second element (at index 1). As others have pointed out, this is covered in the first section of the language guide, “The Basics”. 3 solved What does the .0 and .1 mean Swift 3.0.1
Here is the problem: func(no++); Let’s say no is 32. This will pass 32 to func and then increment it. Which means that you are once again calling the function with a value of 32. And when that function hits this line, it will, once again, pass that 32 to func. Hence, an infinite recursive … Read more
If you’re being LAZY and i mean lazy you can use http://converter.telerik.com/ Here’s the output for you: Public Shared Function getColumnNameFromIndex(column As Integer) As String column -= 1 Dim col As String = Chr(Asc(“A”) + (column Mod 26)) While column >= 26 column = (column \ 26) – 1 col = Chr(Asc(“A”) + (column Mod … Read more
There are two syntax errors in your code: function isEven(value) { //value = Number(value); if (value%2 == 0) // no parens here is allowed so no syntax error return true; else return false; } function testCondition() { // ^^ missing parens here if (isEven(n)) { // ^ ——- ^ — and here } else { … Read more