I will not do your HW, but I will give a hint. When playing around with OpenMp for loops, you should be alert about the scope of the variables. For example: #pragma omp parallel for for(int x=0; x < width; x++) { for(int y=0; y < height; y++) { finalImage[x][y] = RenderPixel(x,y, &sceneData); } } … Read more
doing for( int i =0; i++<10; a[i-1]=i ) { printf(“%i:%i\n”, i-1, a[i-1]); } you set the entries after you print them because a[i-1]=i is executed after the body of the for, so you print non initialized array entries your code is also ‘complicated’ because you increase i too earlier in the test part of for, … Read more
I have read that it is very easy to hack and recompile an unity game. Also, I read that they have a function (provided by the engine) to determine that the game has been recompiled. Yes, Unity has a function to determine if your game has been de-compiled and recompiled or modified in any way. … Read more
Your bot does not respond because the client is not initialized correctly. You’re creating the client like this: var bot = new Discord.Client({ token: auth.token, // <– autorun: true // <– }); The problem is that these arguments do not exist in discord.js, as stated by the Client docs. To log into your bot, please … Read more
Top-level classes cannot be static, because the static keyword represents a relation between a class/member/method and the enclosing class. As the top-level classes don’t have an enclosing class, then the static keyword doesn’t makes sense in this case. solved Applying static keyword to a class in java [duplicate]
Proper method: Int32 weeklySales = 0; while (weeklySales.Equals(0)) { Console.WriteLine(“What are your weekly sales?”); String input = Console.ReadLine(); try { weeklySales = Int32.Parse(input); } catch { Console.WriteLine(“There is an error in your input, try again!”); } } Double grossPay = weeklySales * .07; Double fedTax = grossPay * .18; Double retirement = grossPay * .1; … Read more
You can check every element in the array and break if only the element is smaller than 100. And outside the loop print the message based on whether i – The loop counter- is equal to the size or not. If equal than all elements are greater otherwise one of them is smaller: int array[] … Read more
The problem with your code is this check: if (ch == ‘O’) { if (!((inp.charAt(i + 1)) == ‘X’ || (inp.charAt(i – 1)) == ‘X’)) { count++ } } Here you check for only a case where there is O not surrounded by X. But this check doesn’t work for cases like *OOXOO*. You’ll get … Read more
How can I output the matching portion of two strings, while having the % character separate any non-consecutively matching portions? solved How can I output the matching portion of two strings, while having the % character separate any non-consecutively matching portions?
I figured it out. Just use ob_start(), and loop through each user. Select the posts they’re subscribed to. Then inside the loop email it to each user. I used this query SELECT articles.* FROM articles INNER JOIN subscriptions ON articles.from_id = subscriptions.sub_to INNER JOIN users ON subscriptions.user_id = users.id WHERE users.email = :email 5 solved … Read more
Indentation is essential in Python; it replaces curly braces, semi-colons, etc. in C-like syntax. Consider this code snippet, for example: def f(x): if x == 0: print(“x is zero”) print(“where am i?”) If it weren’t for indentation, we would have no way of indicating what code block the second print statement belongs to. Is it … Read more
This should be about right: func tableView(tableView: UITableView, indexPath: NSIndexPath) { let cell = tableView.cellForRowAtIndexPath(indexPath); let cellText = cell.textLabel.text; } 4 solved TableViewCell in Swift?
In general you can create strings with placeholders using: String result = String.format(“%s,%s”, v1, v2); If you are using JDBC, you can use a PreparedStatement, for example: PreparedStatement statement = connection.prepareStatement(“UPDATE table1 SET column1 = ? WHERE column2 = ?”); int i = 1; statement.setInt(i++, v1); statement.setInt(i++, v2); statement.executeUpdate(); For creating JDBC queries the PreparedStatement … Read more
Your problem is in the merge function: you exceed the local variable c. long c[30]; maybe there are more problems, that is the first I notice. EDIT Try this: find the differences… #include <map> #include <vector> #include <fstream> #include <iostream> #include <time.h> using namespace std; void merge(vector<long> &,long ,long , long ); void divide(vector<long> &arr,long … Read more
It is always a good habit to set the pointer to NULL after freeing it. Since the memory you are accessing is still intact you are seeing right values for l->val. Node *l=malloc(sizeof(Node)); l->key=”foo”; l->val=”bar”; free(l); l = NULL; solved free() not working correctly with struct