[Solved] if and else for visible form [closed]
Is form1 the type of the current instance? If so, change if (form1.Visible) to if (this.Visible) or simply if (Visible). 0 solved if and else for visible form [closed]
Is form1 the type of the current instance? If so, change if (form1.Visible) to if (this.Visible) or simply if (Visible). 0 solved if and else for visible form [closed]
Use this it works….. create boolean variable as global within class but outside methods. boolean flag=true; and add this clicked method. @Override public void onClick(View v) { if (flag){ power.setVisibility(View.GONE); flag=false; } else { flag=true; power.setVisibility(View.VISIBLE);} } }); mute always visible , because you performing visibility with power that why the result coming same. enjoy … Read more
Here is one example: package main import ( “fmt” ) // example struct type Graph struct { nodes []int adjList map[int][]int } func New() *Graph { g := new(Graph) g.adjList = make(map[int][]int) return g } func main() { aGraph := New() aGraph.nodes = []int {1,2,3} aGraph.adjList[0] = []int{1990,1991,1992} aGraph.adjList[1] = []int{1890,1891,1892} aGraph.adjList[2] = []int{1890,1891,1892} fmt.Println(aGraph) … Read more
Low visibility = private. High visibility = public. And there are two more visibilities in-between. From higher to lower visibility: public > protected > “default” > private “Default” doesn’t have a keyword associated, it’s the visibility that applies when no visibility is explicitly declared. And here’s the relevant link from the documentation. solved Visibility of … Read more
Since the question refers to a single element, this code might be more suitable: // Checks CSS content for display:[none|block], ignores visibility:[true|false] $(element).is(“:visible”); // The same works with hidden $(element).is(“:hidden”); It is the same as twernt’s suggestion, but applied to a single element; and it matches the algorithm recommended in the jQuery FAQ. We use … Read more