[Solved] How to sample a column based on frequency in R?
The easiest way would just be to shuffle the column… df$col3 <- sample(df$col3) 3 solved How to sample a column based on frequency in R?
tidyverse
[Solved] Replace values greater than zero with 1 in r
The following will convert all non-zero numeric values to 1: df.richness %>% mutate_if(is.numeric, ~1 * (. != 0)) while df.richness %>% mutate_if(is.numeric, ~1 * (. > 0)) will do that with those greater than zero. solved Replace values greater than zero with 1 in r
[Solved] R: Is there a function to clean factor levels? characters columnwise in a data frame? [closed]
Just use the internal bits from janitor::clean_names(): # #’ ‘Clean’ a character/factor vector like `janitor::clean_names()` does for data frame columns # #’ # #’ Most of the internals are from `janitor::clean_names()` # #’ # #’ @param x a vector of strings or factors # #’ @param refactor if `x` is a factor, return a ref-factored … Read more
[Solved] How to calculate a condition using dplyr?
As I understand it, you want a column that checks if the temperature deviates by 5 – 6 degrees (if the temp is greater than 10) and another column to check if it is differs by 7 degrees or more. The current code you are using seems to identify the coldwave values correctly, although is … Read more
[Solved] Surveydata Package Question, merge columns [closed]
We can use pivot_longer library(dplyr) library(tidyr) # 1.0.0 df1 %>% pivot_longer(cols = matches(“^Q\\d+_\\d+”), values_to = ‘Q1’) %>% select(-name) 4 solved Surveydata Package Question, merge columns [closed]