[ad_1] Try Group by.. Having clause with MAX() to find out players name who never scored century SELECT NAME FROM table GROUP BY NAME HAVING MAX(SCORE) < 100; 4 [ad_2] solved how to retrieve player names who never scored a century?
[ad_1] I would have a guess that you need escape the quotes or use single quotes in your SQL. I would have a stab and say your code is outputting an incorrect format for the links. $url=”<a href=”https://stackoverflow.com/questions/46113161/link.com”>link.com</a>”; ## << This is the value from the database echo $url; As you can see there are … Read more
[ad_1] I think this should work. I used :start and :end as placeholders for your input values. The query selects all employees with their working dates when the working date is at least partially part of your input range. Visualization (I: input range, y: selected, n: not selected): ——–IIIIIIIIIIIIIIIIIIII———- –nnn-yyyy—yyyy———yyyyy—-nn- Query: SELECT * FROM workdates … Read more
[ad_1] Try below – you’ve a syntax error in your query, remove en SELECT * FROM `album` WHERE `prijs` BETWEEN 3 AND 4 [ad_2] solved SQL between-statement [closed]
[ad_1] An inner join should do it. Here’s the syntax, but you’ll have to apply it to your database: SELECT c.name, o.name FROM cats c INNER JOIN owners o ON c.owner_id = o.id “cats c” basically means “Cats table, which I’m nicknaming c.” “owners o” basically means “Owners table, which I’m nicknaming o.” In your … Read more
[ad_1] Replace the for loop with this: while($row=mysqli_fetch_array($result)){ echo “<td><strong>From:</strong>”.$row[“fra”].” <br><strong>To:</strong> “.$row[“til”].” <br><strong>Date:</strong> “.$row[“dato”].” <br><strong>Clock: </strong> “.$row[“klokkeslett”].”</td>”; echo “<td></td>”; echo “<td></td>”; } You are telling you program to keep looping through mysql_fetch_array($result) and assign the fetched record to $row. Also, do not forget to take out this line $countRows=mysqli_affected_rows($db); as you no longer need it. … Read more
[ad_1] What is this little snippet: … p7,ex8,p8,,p3,p4,p5 … ^^ meant to be? That’s a rhetorical question by the way, since at least one commenter didn’t understand that 🙂 That’s where your trouble lies. In fact, since you have 24 column names (excluding the empty one between the commas) and only 18 values to be … Read more
[ad_1] You would need at the very least two tables. One for storing stores and other for products. One table for each store makes little sense to me. 2 [ad_2] solved Stock keeping System [closed]
[ad_1] You can use exceptions. Try this: DECLARE y NUMBER; b emp.ename%TYPE; BEGIN y := :enter_no; SELECT ename INTO b FROM emp WHERE empno = y; EXCEPTION WHEN NO_DATA_FOUND THEN DBMS_OUTPUT.PUT_LINE(b); END; 0 [ad_2] solved VALUE NOT EXIST (SQL)
[ad_1] If your filed is a Date or DateTime, I would use the function DATEPART. For example, this gets the current year: DATEPART(year, GETDATE()) View the msdn page for the full documentation. If your field is text, use CONVERT to convert your field to a DATE, then use the first method with the converted date … Read more
[ad_1] You should show some effort and try to solve it yourself (it’s good for learning if for no other reason), but anyway, this can be done in several ways. This is two: SELECT idt, nome, bool1 FROM path WHERE idt IN ( SELECT idt FROM path WHERE bool1 = ‘true’); SELECT path.idt, nome, bool1 … Read more
[ad_1] Check out this Manual Page: http://dev.mysql.com/doc/refman/5.6/en/cast-functions.html#function_cast CAST(meta_key AS UNSIGNED) should work for you. [ad_2] solved Mysql Update Query cast varchar to string
[ad_1] Better version in a single query: select p1.productname from Product p1, myorder s1, lineitem l1, customer c1 where l1.pid=p1.pid and l1.OID=s1.oid and c1.cid=s1.cid and c1.city=’mycity’ group by p1.ProductName having count(distinct c1.cid)=(select count(1) from customer c2 where c2.city=’mycity’); [ad_2] solved SQL query to retrive data [closed]
[ad_1] select all_people from call_centerDB where called_nos=92222 OR called_nos=122323 OR called_nos=9988898 [ad_2] solved Please help me out for the following scenario [closed]
[ad_1] You can’t edit any files of prestashop at admin. So to edit css files, and .tpl file you have to do it in an editor like DreamWeaver or notepad++ directly. Open the file and edit your required contents in the editor. [ad_2] solved Prestashop – How to edit views [closed]