What is so difficult on D.*-.*/.*? If you want to ensure that there is at least one character for behind the D, – and / respectivly you should use .+ instead of those .*. 0 solved What regex pattern can I use to match this string? [closed]
This substring() expression does what you ask: substring(string, ‘\m\d+\D?*\M’) The regular expression only returns the first match, or NULL if none. \m … beginning of a word\d+ … one or more digits\D? … zero or one non-digits\M … end of word Demo: SELECT string, substring(string, ‘\d+\D?\d*\M’) FROM ( VALUES (‘FLAT 3, thanos house, nw1 6fs’) … Read more
Seeing as you asked for a C# example, Case Insensitive can be selected as one of the RegexOptions. I assumed the 13 was also meant to be a 2 digit number. using System.Text.RegularExpressions; … Regex regX = new Regex( @”(\d{1,2}):(\d{1,2})-([a-z]{2})-(\d{3,5})”, RegexOptions.IgnoreCase ); if( regX.IsMatch( inputString ) ) { // Matched } … solved Regex for … Read more
Don’t use regular expressions to parse HTML. Use BeautifulSoup >>> from BeautifulSoup import BeautifulSoup >>> ht=”<html><head><title>foo</title></head><body><p>whatever: <img src=”https://stackoverflow.com/questions/5878079/foo/img.png” height=”111″ width=”22″ /></p><ul><li><img src=”foo/img2.png” height=”32″ width=”44″ /></li></ul></body></html>” >>> soup = BeautifulSoup(ht) >>> soup <html><head><title>foo</title></head><body><p>whatever: <img src=”https://stackoverflow.com/questions/5878079/foo/img.png” height=”111″ width=”22″ /></p><ul><li><img src=”foo/img2.png” height=”32″ width=”44″ /></li></ul></body></html> >>> soup.findAll(‘img’) [<img src=”https://stackoverflow.com/questions/5878079/foo/img.png” height=”111″ width=”22″ />, <img src=”foo/img2.png” height=”32″ width=”44″ />] >>> for … Read more
This solution can handle all sorts of strings, not only numeric characters. s1 = ‘ABC0123091274723507156XYZ’ # without 8 s2 = ‘ABC0123091274723507156XYZ8′ len(set(“”.join(re.findall(r'([\d])’, s1)))) == 10 # False len(set(“”.join(re.findall(r'([\d])’, s2)))) == 10 # True How it works: Find all digits in the string with regex findall. Join all matches to one string and get unique characters … Read more
With regexp: $str=”http:example.com/country/France/45″; preg_match(‘/http:example\.com\/country\/(?P<name>\w+)\/(?P<id>\d+)/’, $str, $matches); print_r($matches); // return array(“name”=>”France”, “id” => 45); 0 solved Get number from an url in PHP
const regex = /”\w+\|/g; const str = `mmSuggestDeliver(0, new Array(“Name”, “Category”, “Keywords”, “Bias”, “Extension”, “IDs”), new Array(new Array(“Advance Auto Parts Inc.”, “Aktien”, “982516|US00751Y1064|AAP||”, “85”, “”, “Advance_Auto_Parts|982516|1|13715”),new Array(“iShares China Large Cap UCITS ETF”, “Anzeige”, “”, “100”, “”, “http://suggest-suche-A0DK6Z”)), 2, 0);`; let m; while ((m = regex.exec(str)) !== null) { // This is necessary to avoid infinite … Read more
Try the below function function AllowNumbers(e, field) { var val = field.value; var re1 = /(^[0-9$]+)/g; val = re1.exec(val); if (val) { field.value = val[0]; } else { field.value = “”; } } and call this function on keyup of a textbox 2 solved Regex to allow only numbers and $ symbol [closed]
Introduction Regular expressions (regex) are a powerful tool used to match patterns in text. They are used in many programming languages and applications to search, edit, and manipulate text. This article will explain what a regex is and how to interpret a regex. It will also provide an example of a regex and explain what … Read more
The Stack Overflow Regular Expressions FAQ See also a lot of general hints and useful links at the regex tag details page. Online tutorials RegexOne ↪ Regular Expressions Info ↪ Quantifiers Zero-or-more: *:greedy, *?:reluctant, *+:possessive One-or-more: +:greedy, +?:reluctant, ++:possessive ?:optional (zero-or-one) Min/max ranges (all inclusive): {n,m}:between n & m, {n,}:n-or-more, {n}:exactly n Differences between greedy, … Read more
Locked. There are disputes about this answer’s content being resolved at this time. It is not currently accepting new interactions. You can’t parse [X]HTML with regex. Because HTML can’t be parsed by regex. Regex is not a tool that can be used to correctly parse HTML. As I have answered in HTML-and-regex questions here so … Read more
I’ve came up with this regex, which might work in most cases but not all. Since you said you might have broken regex, it’s hard to know what the output will look like. Anyways, this might work fine for your needs. r'”intent_path”:(?: ?)”([\w\s,]+)”‘ You can test more cases here 1 solved Parse JSON String with … Read more
Try with JSON library sample code: JSONObject jsonObject = new JSONObject(jsonString); JSONObject innJsonObject = jsonObject.getJSONArray(“entries”).getJSONObject(0); System.out.println(innJsonObject.get(“pageref”)); // page_0 System.out.println(innJsonObject.get(“time”)); // 515 You can try with GSON library as well. sample code: Gson gson = new Gson(); Type type = new TypeToken<Map<String, ArrayList<Map<String, Object>>>>() {}.getType(); Map<String, ArrayList<Map<String, Object>>> data = gson.fromJson(reader, type); Map<String, Object> map = … Read more
This looks like a json object but doesn’t have [] around it to make it an actual list. You should be able to convert it into a Python native list of dictionaries and navigate it: import json recipe = json.loads(‘[‘ + your_text + ‘]’) steps = [obj[“text”] for obj in recipe if obj.get(“@type”) == “HowToStep”] … Read more
Try the regular expression ^\\d{10,15}$ Here \d is a predefined character class for digits{10, 15} quantifier stands for a repeat of 10 to 15 times of the previous pattern Ex: String input = “1234567890”; Pattern pattern = Pattern.compile(“^\\d{10,15}$”); if (pattern.matcher(input).find()) { System.out.println(“Valid”); } 0 solved Phone number validation regex for length and numeric values [duplicate]