You’re asking to match any number of lines of text, followed by only 1 additional newline at the end, simply: ^(.+\n)+\n(?!\n) will do what you’d like. Example here: https://regex101.com/r/Hy3buP/1 Explanation: ^ – Assert position at start of string (.+\n)+ – Match any positive number of lines of text ending in newline \n – Match the … Read more
#!/usr/bin/python2 # -*- coding: utf-8 -*- import re text=”{[FACEBOOK23.1K],[UNKNOWN6],[SKYPE12.12M]}”; m = re.findall(‘\[([a-z]+)([^\]]+)\]’, text, re.IGNORECASE); output=”{“; i = 0 for (name,count) in m: if i>0: output += ‘,’ output += “[“+name+”,”+count+”]” i=i+1 output += ‘}’ print output 4 solved Regex to seperate a work and decimal number
This will do it for you: ^[\w.]+=\$\d+(?:\|[\w.]+=\$\d+)*$ It matches at least one word character or . followed by an =, $ and a digit. Then, optionally, a | followed by the first sequence again. This optional part can be repeated any number of times. See it here at regex101. Edit Allow multi-digit numbers. Edit 2 … Read more