I have solved it. The problem was NoSuchElementException for the line: n=scanner.nextInt(); I have fixed it using: if(scanner.hasNextInt()) { n = scanner.nextInt(); } The code has been accepted by uHunt. solved UVa 562 runtime error. What can I do? [closed]
If I understand correctly what you’re asking, something like this should satisfy it, but please note that recursion is not really the best way to achieve what you’re apparently trying to do: public static void count(ArrayList<Double> list) { if (list.empty()) { return; // or consider using if/else } double total = total(list); if (total>100) { … Read more
tl;dr; The method defined is recursive, you can call it enough times to force an Exception of type Recursion Error because it adds to the stack every time it calls itself. Doesn’t mean it’s the best approach though. By definition a recursive function is one that is meant to solve a problem by a finite … Read more
Try this? def numberToList(number): # base case if number == 0: return [] # recurse return numberToList(number / 10) + [ number % 10 ] Run it like this: >>> numberToList(1234) [4, 3, 2, 1] 1 solved append all Integers of an integer in a list in python using recursive function [closed]
What about something like the following? int cifminpar(const int x) { if(!x) return 11; //recursive call int minrest=cifminpar(x/10); //min even in the rest of the digits if(x % 10 % 2 == 0) return min(minrest , x%10 ); return minrest; } It returns 11 if no even digits are found and work as follows and … Read more
The code behaves as expected, the power function is recursive. For arguments 4 and 2, it calls itself recursively twice: power(4, 2) -> 4 * power(4, 1) -> 4 * (4 * power(4, 0)) -> 4 * (4 * 1) -> 16 You might be more familiar with an iterative approach: int power(int base, int … Read more
You have one problem on line 1 of your Bik Method: Every time you call it the variable sum is defined to 0 so it never changes. Also in your code you never actually sum the value from the previous iteration. The solution I can come with is to pass another parameter with the sum … Read more
The code below is messy and un-commented, but I’m glad it was able to get you in the right direction, so you were able to figure out the solution! Downloadable MDB on JumpShare here. Option Compare Database: Option Explicit ‘I had a theory which I implemented and later commented out in order to handle “two-direction … Read more
Okay, here’s an example implementation. It uses the following values for tiles: 0 to 8: an unmined tile; the number represents the pre-calculated number of adjacent mines 9: a mine; this special value is defined as BOMB. Covered tiles have 10 added to that, flagged tiles (not used here) have 20 added to that. You … Read more
Here is a demonstrative program written in C++ that you can use as an algorithm and rewrite it in C #include <iostream> #include <iomanip> #include <stack> #include <cstring> bool balance( const char *s, std::stack<char> &st ) { const char *open = “({[<“; const char *close = “)}]>”; if ( *s == ‘\0’ ) { return … Read more
You must protect against dividing by zero. Specifically, any time the value of q may be zero. At a minimum you need to test q each time you enter your function. With the additional code you posted, if you insure q isn’t 0 before calling geoprogress, that is sufficient as well. Regardless, a test in … Read more
You would want to write a recursive function to do this. For each Tree constructor, you’ll need a different case in your function. To start with, you know that the depth of any Leaf is 1, so maxDepth :: Tree -> Int maxDepth (Leaf _) = 1 maxDepth (Branch2 c left right) = maximum [???] … Read more
You do not need anywhere near that many entries (10^9 / 3). Note that you need only the values mod 10^6. You have a recurrence relationship among these: a[n] = a[n-1]^2 + 2 Each value depends only on the previous one, so there will be a simple sequence of numbers. The relation will have a … Read more
Do something like this… <?php $inc=2; recv(7); // Calling your recursive function i.e. passing the parameter 5 or 7 function recv($v) // Your function definition { global $inc; if($v>=1) { echo $inc*$v.” “; $v–; recv($v); // Function calls itself in other words “recursive call” } } OUTPUT : 14 12 10 8 6 4 2 … Read more
The classic recursive implementation of fib is this: int fib(int n) { if (n < 2) return n; else return fib(n – 1) + fib(n – 2); } This function recurses so many times, it is used as an easy benchmark to measure function call efficiency in various languages, with a time complexity of O(φn). … Read more