[ad_1] I am supposing your csv will be like this: user1, hash_pass_u1 user2, hash_pass_u2 user3, hash_pass_u3 … Just one note before the solution. You are importing the CSV module of Python and you did not use it in your code, such a silly import, just use it. The solution is simple import csv file=”yourcsv.csv” found … Read more
[ad_1] You could try chunking every 25 lines, then write them each out to separate files: def chunks(l, n): “””Chunks iterable into n sized chunks””” for i in range(0, len(l), n): yield l[i:i + n] # Collect all lines, without loading whole file into memory lines = [] with open(‘FileA.txt’) as main_file: for line in … Read more
[ad_1] You’re looking for the len method, which works on any object with a definable length: >>>test_string = “Hello” Hello >>>len(test_string) 5 For a string, it will treat the string as a list of characters. This means “Hello” has 5, but “Hello ” would have 6, and “Hello World!” would have 12. docs: https://docs.python.org/3/library/functions.html#len [ad_2] … Read more
[ad_1] First the final answer, which is really a one-liner. Some explanations follow a = [88, 24, 128, 3] [i + 1 for i, x in enumerate(“”.join(bin(n + 256)[3:] for n in a)) if x == “1”] This yields [2, 4, 5, 12, 13, 17, 31, 32] First transformation: def dec2bin(a): return [int(x) for x … Read more
[ad_1] Code it from scratch. If you’re not going to use an external library, that is by definition pretty much your only option. You’ll want to become an expert in the formal specifications for both PDF and MS Word. Given the complexity and history of each of those, I expect a senior developer will want … Read more
[ad_1] You can use str.format, and str.join to get your required output. Ex: fruits = [‘banana’, ‘apple’, ‘plum’] mystr=”i like the following fruits: \n\n{}”.format(“\n”.join(fruits)) print(mystr) Output: i like the following fruits: banana, apple, plum 3 [ad_2] solved Concatenate string & list [duplicate]
[ad_1] Your version does not work because index always get the first match. And this code is way cleaner and shorter: def search_for_string(lists,str1): list2=[] for index, value in enumerate(lists): if value==str1: lists[index] = ‘xxxxx’ list2.append(index) return list2 sample_list = [“artichoke”, “turnip”, “tomato”, “potato”, “turnip”, “turnip”, “artichoke”] print(search_for_string(sample_list, “turnip”)) Output : C:\Users\Documents>py test.py [1, 4, 5] … Read more
[ad_1] import random n = int(input(‘Введите кол-во столбцов матрицы: ‘)) #columns m = int(input(‘Введите кол-во строк матрицы: ‘)) #rows matrix = [[random.randrange(0, 10) for y in range(n)] for x in range(m)] for i in range(m): for j in range(n): print(matrix[i][j], end = ” “) print() max_x = 0 for i in range(m): for j in … Read more
[ad_1] It should be: from django.template.library import TagHelperNode Reference can be found here. 1 [ad_2] solved How can I adjust my code to adapt the Django upgrade?
[ad_1] You could try Steven Masfaraud’s block module simulator (BMS). As of August 2016 it has nonlinear block elements for Saturation, Coulomb, Dead Zone, and Hysteresis. Here’s a link to one of his examples. The other option on this Quora post is PyLinX. It looks like SciPySim may no longer be under development, from this … Read more
[ad_1] I think you have a simple, one-line change. You get the name instead of the index, because that’s exactly what you told it to print. Instead, use this: print(‘The index of this name is ‘, index) Your original went to the extra trouble to look up the name in that location. 1 [ad_2] solved … Read more
[ad_1] Using a for loop: acc = 0 for num in list1: acc += num Another approach: acc = sum(list1) [ad_2] solved Handling numbers in lists (Python) [duplicate]
[ad_1] json.dump() takes two arguments, the Python object to dump and the file to write it to. Make your changes first, then after the loop, re-open the file for writing and write out the whole data object: with open(“app.json”) as json_data: data = json.load(json_data) for d in data[’employees’]: d[‘history’].append({‘day’: 01.01.15, ‘historyId’: 44, ‘time’: 12.00}) with … Read more
[ad_1] You can wrap your lambda using reduce: >>> from functools import reduce >>> >>> lst = [22, 36, 47, 2, 13] >>> reduce(lambda x, y: x if (x > y) else y, lst) 47 [ad_2] solved Use a lambda function to find the maximum of a list in python [closed]
[ad_1] This is reading the file line-by-line, and finishing at the first empty line, meaning the end of the file. breakexits the while True;loop It’s horrible code though; cases where you actually need to manually code a loop like this a pretty rare in python. More succinct/pythonic would be something like: for buffer in fp.readlines(): … Read more