[Solved] TypeError(“unsupported operand type(s) for ** or pow(): ‘str’ and ‘int'”,)
Try doing B = float(input( “Enter Height in meters : “)) 2 solved TypeError(“unsupported operand type(s) for ** or pow(): ‘str’ and ‘int’”,)
Try doing B = float(input( “Enter Height in meters : “)) 2 solved TypeError(“unsupported operand type(s) for ** or pow(): ‘str’ and ‘int’”,)
When python searches for a module to import, it first uses sys.modules or the built-in modules: When a module named spam is imported, the interpreter first searches for a built-in module with that name. If not found … Since there is already an abc module you’re importing the wrong module. Change the name of your … Read more
You need to know the format of the response to parse it. I saw, that you used requests.get(). After your get request request = requests.get(…) request.json() will return a dict object of your JSON response. It looks like that (after formatted, used the codes like of @Alex): {u’sort’: u’relevance’, u’items’: [{u’marketplace’: False, u’imageEntities’: [ {u’entityType’: … Read more
One way to think about recursion is to try and solve only a small piece of the problem, and then imagine that recursive call ‘magically’ solves the rest of the problem. Importantly, you have to consider what happens when the rest of the problem is trivial to solve; this is called the base case. In … Read more
All you need to do is print (sentence[2:]) For future reference and research, it is called slice. solved Python – Is there a way to use a greater than operator that is not a comparison operator?
Here: def make_pattern(file_path, n): with open(file_path,’w’) as f: f.write(‘\n’.join([‘*’*(i+1) if (i+1)%2 else ‘#’*(i+1) for i in range(n)])) # write each string in the list joined by a newline make_pattern(“t.txt”, 5) Output file (t.txt): * ## *** #### ***** solved Create a pattern that looks like this in a file with n number of lines
Face culling This works only for single convex strict winding rule mesh without holes! The idea is that sign of dot product of 2 vectors will tell you if the vectors are opposite or not. So if we have a normal pointing out and view direction their dot should be negative for faces turned towards … Read more
You should use the bs4.Tag.find_all method or something similar. soup.find_all(attrs={“face”:”arial”,”font-size”:”16px”,”color”:”navy”}) Example: >>>import bs4 >>>html=””‘<div id=”accounts” class=”elementoOculto”> <table align=”center” border=”0″ cellspacing=0 width=”90%”> <tr><th align=”left” colspan=2> permisos </th></tr><tr> <td colspan=2> <table width=100% align=center border=0 cellspacing=1> <tr> <th align=center width=”20%”>cuen</th> <th align=center>Mods</th> </tr> </table> </td> </tr> </table> <table align=”center” border=”0″ cellspacing=1 width=”90%”> <tr bgcolor=”whitesmoke” height=”08″> <td align=”left” width=”20%”> … Read more
Keep the variable a outside loop. def deviser(n): a=[]; i=1; while( i<= n): x=n%i; if( x == 0 ): p = a.insert(0, i); print i; i = i+1; return a; >>> deviser(18) 1 2 3 6 9 18 [18, 9, 6, 3, 2, 1] >>> solved How can i make self updating list in python?
No, you cannot have exactly that. However, if there some reason why you really need to have a string at the beginning of a line (and note that this not a recommended style at all in Python), you can write: ”’ This line is imperative: ”’; x = 5 Note the ; after the string. … Read more
If your object isn’t a dict but could be converted to a dict easily (e.g. list of pairs), you could use: def make_a_dict(some_object): if isinstance(some_object, dict): return some_object else: try: return dict(some_object) except: return {‘return’: some_object} print(make_a_dict({‘a’: ‘b’})) # {‘a’: ‘b’} print(make_a_dict([(1,2),(3,4)])) # {1: 2, 3: 4} print(make_a_dict(2)) # {‘return’: 2} solved how to make … Read more
Since you did not post your error that you are getting with pip, I can only comment on the conda install problem. python-docx is not available from the default channels, but from conda-forge. So use this to install: conda install -c conda-forge python-docx solved why python-docx is not found in
num is string. >>> num = ( “which no. u want to check prime or not:” ) >>> num % 1 Traceback (most recent call last): File “<stdin>”, line 1, in <module> TypeError: not all arguments converted during string formatting >>> I think you missed raw_input(): >>> num = int(raw_input( “which no. u want to … Read more
You don’t need a regex, look for the apostrophe following the backslashes and replace the whole pattern with just an apostrophe: In [1]: s = “It was quick and great ! And it\\\\’s customized” In [2]: s.replace(r”\\'”, “‘”) Out[2]: “It was quick and great ! And it’s customized” Based on your repr output you don’t … Read more
You can open the file and get the lines as a string using: with open(“/path/to/file.txt”) as file: lines = list(file) This will give you a list of all lines in the text file. Now since you do not want duplicates, I think using set would be a good way. (Set does not contain duplicates) answer=set() … Read more