python

you can add a counter to the loop condition. c = 0 while c < 3: try: .. except … c = c + 1 2 solved While loop limit times [duplicate]

You can iterate over the list and extend it with the reversed elements: List = [[[‘1′,’2’],[‘2′,’4’]],[[‘1′,’4’],[‘4′,’8′]],[[’53’,’8′],[‘8′,’2’],[‘2′,’82’]]] for sublist in List: sublist.extend([pair[::-1] for pair in sublist]) In the end, List will be: [[[‘1’, ‘2’], [‘2’, ‘4’], [‘2’, ‘1’], [‘4’, ‘2’]], [[‘1’, ‘4’], [‘4’, ‘8’], [‘4’, ‘1’], [‘8’, ‘4’]], [[’53’, ‘8’], [‘8’, ‘2’], [‘2′, ’82’], [‘8′, ’53’], … Read more

This relies on the list of lists being sorted in ascending length (and the outputs needs sorting), but works with all provided input as of time of posting. def removeFromList(elementsToRemove): def closure(list): for element in elementsToRemove: if list[0] != element: return else: list.pop(0) return closure def func(listOfLists): result = [] for i, thisList in enumerate(listOfLists): … Read more

Maybe this will help. In your case, def action(file1, file2, behavior=defaultBehavior): return behave(file1, file2) is okay. But of course, if an argument is passed into the “behave” parameter, you should take care of it in your function. For instance, if you called action(“somefile”, “anotherfile”, customBehavior) then you’ll want something like the following to deal with … Read more

Edit: I didn’t catch what the other two answers said about how you’ve changed Class so that it will never equal 1, 2, 3. changing your if clauses to if Class == “1.txt”: #code elif Class == “2.txt”: #code elif Class == “3.txt”: #code else: #code to deal with Class not being what you think … Read more

The parentheses on the while loop are not Python syntax, try: while a <= 999…: # colon, not parenthesis a += 1 # not just a + 1, you need to assign back to a too print(…) Or, more Pythonic: for a in range(999…): print(…) 2 solved (“”) printing not working in python [closed]