This operator+ is used here (a pointer to single char that is not null-terminated is not really suitable). Yes, most definitely undefined behavior. lhs – string, character, or pointer to the first character in a null-terminated array Just make std::string the common type to fix it: ((d == ‘\0’) ? std::string(“null character”) : std::string(1, d)) … Read more
Is it valid statement int P* ? No, it won’t compile. What’s the difference between int * p and int p* ? int * p; Here p is integer pointer . And int p* is an invalid syntax. 0 solved Whats the difference between int * p and int p*? [closed]
It would help to see how you push items onto the stack. If you’re really calling pop without a push first, well, then it’s not supposed to do anything, is it? This bit makes me nervous: Node *aux,*prev; prev = *stack; aux = prev->next; if(aux == NULL) { free(prev); return; } You set prev to … Read more
((short *)((((char *)(&arr[1])) + 8))[3] = 100 &arr[1]: is the address of the second int in arr (1*sizeof(int) from start). ((char *)(&arr[1])) : converts int address to a char address (((char *)(&arr[1])) + 8) : adds 8 bytes to the char address ((short *)((((char *)(&arr[1])) + 8)): converts the char address to a short address … Read more
I don’t really understand exactly what you are asking, but it sounds like you want to have a way to get the album from a PlaylistTrack. class PlaylistTrack : public Track { public: PlaylistTrack(Album * owner){ m_owner = owner; } Album* getAlbum(){return m_owner;} private: Album* m_owner; } int main() { Album albumA; PlaylistTrack newTrack(&albumA); //Now … Read more
I eventually figured it out. As I kept saying, the problem was in how I was populating the array. Here’s an entire section of code using a for loop which correctly populates my pointer array: #include <iostream> #include <fstream> #include <string> #include <new> using namespace std; int main() { int * arraySize; arraySize = new … Read more
You have a few errors, can you try this: void load(char *name, float *share, float *buyprice, float *currprice) { printf(“Enter stock name”); gets(name); printf(“Enter share, buyprice, currprice”); scanf(“%f %f %f”, share, buyprice, currprice); // changes: removed &* } void calc(float share, float buyprice, float currprice, float *buytotal, float *currtotal, float *profit) { *buytotal = share … Read more
They are very different things. An int** is a pointer to a pointer to an int. If you dereference it, you get an int*. An int* is a pointer to an int. If you dereference it, you get an int. In the first example, you pass an int** with value 0x4df73c as the first argument … Read more
constructArray doesn’t actually do anything relevant, set aside leaking memory. Same for printArray. I guess you began to code in c++ not that long ago, the code you’ve written does the following: void constructArray (No *Number, int size) { // allocates enough memory to store n=size pointers to No then constructs them // stores the … Read more
Introduction When working with data structures, it is often necessary to access an array of pointers to structures. This can be a tricky task, as it requires knowledge of both the array and the structure. In this article, we will discuss how to access an array of pointers to structures, as well as some tips … Read more
It prints “Hello” because operator << has an overload for const char* (which is what you’re passing if you pass x) that prints out a single char and moves to the next char until a NUL-character is found. “Hello” has a compiled-added NUL-character at the end, so your string is actually “Hello\0”. To get the … Read more
You declared a as an array of int**, so *a is not a pointer to int but a pointer to pointer to int. Incrementing a pointer adds the size of the data type it points to, so ++*a advances the value at at a[0] by the size of a pointer. What you actually stored in … Read more
Yes, when you say point3 = (char*)point You are converting the integer pointer point to a character pointer point3. point is designed for pointing at whole integers (which of course are multibyte quantities), while point3 can point at individual bytes. So now point3 points at the individual bytes that point points to, or in other … Read more
The floating point number 100.0 is represented as 0x42C80000 in memory, which in decimal is 1120403456. You’re printing out the 32-bit integer representation of 100.0. 4 solved why float type pointer addressing int showing unknown numbers?
In C, string operations cannot have a convenient interface, because of memory management. If a function receives a string, and converts it to another string, you should decide how to declare its interface. The simplest interface is in-place (strtok uses it); you can use it only if the output is somehow smaller than input: void … Read more