I think that this code you could use int nl= image.rows; int nc= image.cols * image.channels(); for (int j=0; j<nl; j++) { uchar* data= image.ptr<uchar>(j); for (int i=0; i<nc; i++) { data[i]= data[i]/div*div + div/2; } } solved How can I access each pixel in OpenCV, perform an operation and return the new information to … Read more
Because the program didn’t explicitly specify a format for the data output, sharp generated the output in the same format as the image source. In this case the input format was PNG, so your data buffer content is also in PNG format. That’s why the first 8 bytes of data are the standard PNG file … Read more
Since you tagged this with C++, I would use std::vector objects mixed with the std::sort() algorithm for making it easy to find these stats. Here’s a simple example. #include <algorithm> #include <iostream> #include <vector> int main() { std::vector<float> numbers = { 1, 4, 3, 2 }; std::sort(numbers.begin(), numbers.end()); // numbers = { 1, 2, 3, … Read more