[ad_1] I figured it out. See below for the code. INSERT INTO Results (eventID,Result1,Result2,Result3,Result4,Result5) SELECT eventID, [1] as Result1, [2] as Result2, [3] as Result3, [4] as Result4, [5] as Result5 FROM (SELECT [inputTable].eventID,[inputTable].eQualType,[inputTable].Value1 FROM eventQData WHERE eQualType IN (1, 2, 3, 4, 5) AND (Value2 > 0) ) AS inputTable PIVOT (MAX(Value1) FOR [eQualType] … Read more
[ad_1] I can’t explain this Let me explain it for you. You are looking for pivoting the comments values for the concern for each student. Unfortunately, MySQL has no pivot table operator. However, you can use the CASE expression to do this. Like so: SELECT student_name, MAX(CASE WHEN concern = ‘Academics’ THEN comments END) AS … Read more
[ad_1] I usually use dynamic sql. Something like this create table #T ( ID int, aText1 varchar(4), aText2 varchar(4), aInt1 int, aInt2 int ) insert into #T select 1, ‘ABC1’, ‘XYZ1’, 2, 20 union select 2, ‘ABC1’, ‘XYZ2’, 3, 25 union select 3, ‘ABC2’, ‘XYZ2’, 1, 30 union select 4, ‘ABC2’, ‘XYZ1’, 4, 35 declare … Read more
[ad_1] Since you are using SQL Server then you can implement the PIVOT function and if you have an unknown number of period values, then you will need to use dynamic SQL: DECLARE @cols AS NVARCHAR(MAX), @query AS NVARCHAR(MAX) select @cols = STUFF((SELECT distinct ‘,’ + QUOTENAME(‘PeriodId’+cast(periodid as varchar(10))) from Periods FOR XML PATH(”), TYPE … Read more
[ad_1] Your description of what you want for the desired the result is not exactly clear but it seems like you can use the following to get the result. This get the total number of rows per username on each of the previous 5 days (based on the max date) as well as the total … Read more
[ad_1] Maybe I’m missing something but doesn’t this work for you? agg = df.groupby(‘number_of_genres’).agg(‘sum’).T agg[‘totals’] = agg.sum(axis=1) Edit: Solution via pivot_table agg = df.pivot_table(columns=”number_of_genres”, aggfunc=”sum”) agg[‘total’] = agg.sum(axis=1) 2 [ad_2] solved Pivoting a One-Hot-Encode Dataframe
[ad_1] library(tidyr) df %>% gather(value=”amount”,key=’Type’,-SubDept2) %>% head(n=5) SubDept2 Type amount 1 Admin BasicSalary 10000 2 Bar BasicSalary 9880 3 Entertainment BasicSalary 11960 4 F&B BasicSalary 9680 5 Finance BasicSalary 10310 2 [ad_2] solved How to pivot my data frame in R so that it turns into another data frame in this specific format? [duplicate]
[ad_1] In order to get the result that you want you will have to apply both the UNPIVOT and the PIVOT functions. The unpivot function will convert your Q1, Q2, Q3, and Q4 columns into rows. Once that is done, you will apply the pivot function. The unpivot code will be similar to this: select … Read more
[ad_1] A straight-up PIVOT in concert row_number() with should do the trick Select * From ( Select ID = fd_Interpretation ,Item = concat(‘Word’,row_number() over (partition by fd_Interpretation order by fd_Word) ) ,Value = fd_Word From YourTable ) src Pivot ( max( Value ) for Item in ([Word1],[Word2],[Word3],[Word4],[Word5],[Word6],[Word7],[Word8]) ) pvt 2 [ad_2] solved SQL group data … Read more
[ad_1] The basic pattern you want is to have a case expression for each month, and only show the amount if the monthmatches: select account, day, center, entity, year, frequency, case when month=”Jan” then amount end as jan, case when month=”Feb” then amount end as feb, case when month=”Mar” then amount end as mar, — … Read more