[Solved] Notice: Undifined variable: [value] [duplicate]

Introduction This question is related to a common issue encountered when programming in PHP. The error message “Notice: Undefined variable: [value]” indicates that a variable has been used in the code without being declared or assigned a value. This can lead to unexpected results and can be difficult to debug. In this post, we will … Read more

[Solved] Warning: strtotime() expects parameter 1 to be string

$startdate and $enddate are DateTime objects, not strings. strtotime() requires a string, and you should simply pass a string instead, like so: $startdate = “2013-11-15”; $enddate = “2013-11-20”; I’d recommend ugprading to a higher PHP version, if possible. DateTime class is the best way to go when you’re dealing with times and dates in PHP. … Read more

[Solved] Create a table dynamically , number of row depend of select number

this is the ajax code i used: Hello, this is the ajax code i used: <script> $(document).ready(function(){ $(‘#nb_tgbt’).change(function(){ var nbretgbt_id = $(‘#nb_tgbt’).val(); if(nbretgbt_id != 0) { $.ajax({ type:’post’, url:’getvalue.php’, data:{id:nbretgbt_id}, cache:false, success: function(returndata){ $(‘#tablename_tgbt’).html(returndata); } }); } }) }) </script> solved Create a table dynamically , number of row depend of select number

[Solved] How I can get all values using javascript from html table, into array associative or something

var names = document.getElementsByClassName(“first”); var quantities = document.getElementsByClassName(“quantity”); var costs = document.getElementsByClassName(“cost”); var books = []; for(var i=0; i < names.length; i++) { name = names[0].innerText; quantity = quantities[0].value; cost = costs[0].innerText; books.push({name:name, quantity:quantity, cost:cost}); } console.log(books); Here’s the jsfiddle http://jsfiddle.net/8c0cwxh7/4/ solved How I can get all values using javascript from html table, into array … Read more

[Solved] PHP – Showing different text between different dates (3 Different Text to be shown)

Hello Akshat please find the simplified solution below <?php $current_date = date(‘Y-m-d’); if(strtotime($current_date)>strtotime(‘2015-01-01’) && strtotime($current_date)<strtotime(‘2015-04-01’)) { echo “TERM 1”; } elseif(strtotime($current_date)>strtotime(‘2015-04-20’) && strtotime($current_date)<strtotime(‘2015-06-01’)) { echo “TERM 2”; } elseif(strtotime($current_date)>strtotime(‘2015-07-01’) && strtotime($current_date)<strtotime(‘2015-10-31’)) { echo “TERM 3”; } ?> I have tested it and its working fine 1 solved PHP – Showing different text between different dates … Read more

[Solved] Warning: strtotime() expects parameter 1 to be string

Introduction The “Warning: strtotime() expects parameter 1 to be string” error is a common issue encountered when working with PHP. This error occurs when the strtotime() function is used with an invalid parameter. The strtotime() function is used to convert a string representation of a date and time into a Unix timestamp. This error can … Read more

[Solved] #document in Object [closed]

Your developer tools are showing you the content located at the relative URL http//img.youtube.com/vi/$youtube/0.jpg (which is a blank HTML document). You are missing a : and should be using an <img> rather than an <object>. solved #document in Object [closed]

[Solved] Empty query no matter what

You need to fix the backticks and quoting on your query. You have – $sql=`SELECT * FROM PRICES WHERE TES LIKE “%” . $TES . “%” `; It should be – $sql=”SELECT * FROM PRICES WHERE TES LIKE ‘%” . $TES . “%’ “; You should only have to check for a query error once … Read more