[ad_1] Your code is not clear enough ! because the CASE statement is used after using the switch statement but as i see their were no switch statement in your code so i don’t know if this is a type or not Then the using of the case must be look like this : switch(VARIABLE_NAME) … Read more
[ad_1] Something is wrong with query check with print mysql_error(); Check query. quote properly values assigned in query. $query = mysql_query(“SELECT jos_comprofiler.firstname, jos_comprofiler.lastname, jos_users.username, jos_comprofiler.cb_country, jos_users.email FROM jos_users LEFT JOIN jos_comprofiler ON jos_users.id=jos_comprofiler.id WHERE jos_users.id ='”.mysql_real_escape_string($id).”‘”); 2 [ad_2] solved mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/virtua15/public_html/main/1515/dafreg.php on line 9 [duplicate]
[ad_1] You need to swap the $con and $que paramters in your mysql_query function. http://php.net/manual/en/function.mysql-query.php 3 [ad_2] solved Warning: mysql_query() expects parameter 1 to be string [closed]
[ad_1] You mean this? (window.location.pathname + window.location.hash) == ‘index.php#products’ ? ‘index.php#products’ : ‘javascript.void’ window.location / W3Schools 0 [ad_2] solved How convert php line into javascript?
[ad_1] I discovered that my browser and wget both add a non-empty user agent field in the header, so I am assuming Goutte sets nothing here. Adding this header to the browser object prior to the fetch fixes the problem: // Load a crawler/browser system require_once ‘vendor/goutte/goutte.phar’; // Here’s a demo of a page we … Read more
[ad_1] I found two errors in your query additional , at the end of field list and missing ‘ in where condition. Update it to following: if (mysqli_query($db,”UPDATE division2 SET Pos=””.$pos.””, played ='”.$played.”‘, won ='”.$won.”‘, drawn ='”.$drawn.”‘, lost=””.$lost.””, goalsfor=””.$goalsfor.””, goalsag ='”.$goalsag.”‘, goalsdif=””.$goaldif.””, points=””.$points.”” WHERE team = ‘Treaty Celtic'”) === true) { 3 [ad_2] solved how … Read more
[ad_1] It will depend on what your putting the objects into. The objects you’ve been given are just fine, but in order to access the values inside them you will need to access them via the DisplayName property. $.each(results, function(i,e) { console.log(e.DisplayName); }) This would log XXX Street Middle School, XXXX Schools, etc. To circumvent … Read more
[ad_1] You must tell the server to parse the PHP code as PHP code, using PHP tags: <br>Your Interest Rate is: <a style=”color:red;”><?php echo $interest_rate; ?>%</a><br> [ad_2] solved Color PHP variable in html [duplicate]
[ad_1] As you showed no effort in solving your problem, make effort in understanding this): echo count($check[‘offer’]) == count(array_intersect($check[‘basket’], $check[‘offer’])) ? ‘All present’ : ‘Nope’; 1 [ad_2] solved Check if values are present in an array based on another array [duplicate]
[ad_1] <?php $items = [‘mani’ , ‘mani’, ‘nithi’, ‘nithi’, ‘basto’]; $counts = array_count_values($items); // Remove elements that occur more than once. $filtered = array_filter($items, function ($item) use ($counts) { return $counts[$item] === 1; }); var_export($filtered); Output: array ( 4 => ‘basto’, ) [ad_2] solved How to return array unique value? in php [closed]
[ad_1] Here’s something to get you going: How it works Since you’re learning, here’s a brief explanation of how it works. First, assign our string to a variable ($str). Next, we create a temporary string to store the reversed version of the string in, $results. Next, we iterate through $str backwards, appending the character to … Read more
[ad_1] <?php wp_enqueue_script(‘jquery’); wp_enqueue_media();//enqueue these default wordpress file ?> <div> <label for=”image_url”>Picture:</label> <img scr=”” id=”image_url2″>//for show instant image <input type=”hidden” name=”image_url2″ id=”image_url_2″ class=”regular-text” value=””> <input type=”button” name=”upload-btn” id=”upload-btn-2″ class=”button-secondary” value=”Upload Image”> </div> ———————————javascript——————————- $(‘#upload-btn-2’).click(function(e) { e.preventDefault(); var image = wp.media({ title: ‘Upload Image’, // mutiple: true if you want to upload multiple files at once … Read more
[ad_1] You’re doing well, just apply a filtering function to each row you recieve: // SO UPDATE THE QUERY TO ONLY PULL THAT SHOW’S DOGS $query = “SELECT * FROM result WHERE first IS NOT NULL”; $result = mysqli_query($connection, $query); if (!$result) { trigger_error(“Query Failed! SQL: $query – Error: “. mysqli_error($connection), E_USER_ERROR); } else { … Read more
[ad_1] May be its halepful:- :-here you put integer 10 in $counter variable <?php $counter = 10; ?> now in while loop you do a process like:-you put integer 3 in the variable $counter again. so after completing this process (putting integer 3 in the $counter variable) the process return true the while loop will … Read more
[ad_1] Numbers prefixed with 0 are treated as octal numbers: $x = 012;//$x is 10 Details here The reason that $x = ‘012’; works is because PHP converts that to an integer without treating it as an octal number. 0 [ad_2] solved Number with 0 on the front? [closed]