[ad_1] A left outer join assuming the first table is used first. A SQL syntax for the above would be: SELECT * FROM Table1 LEFT JOIN Table2 On Table1.ID1=Table2.ID2 [ad_2] solved Joining two tables without filtering the data on the basis of joining condition
[ad_1] According to my understanding, if you want to save info with then take db structure as: whois_table { id (num)(pk) ip (varchar) info(long text) } Assume you have info like: http://www.whois.net/whois/facebook.com $ip = IP who’s whois info to be inserted $info = whois info of ip INSERT INTO whois_table (ip, info ) values ($ip, … Read more
[ad_1] <?php $conn = mysql_connect(‘localhost’, ‘mysql_user’, ‘mysql_password’); if (!$conn) { die(‘Could not connect: ‘ . mysql_error()); } mysql_select_db(‘database’); $result = mysql_query(‘select URL from table’); if (!$result) { die(‘Query failed: ‘ . mysql_error()); } echo mysql_result($result, 0); // outputs mysql_close($conn); ?> 0 [ad_2] solved How to get a particular cell from MySQL table using PHP? [closed]
[ad_1] when you run a DELETE command, I believe nothing is returned, thus you can’t mysql_fetch_array(). You would normally use that if you’re doing a SELECT. in this case, you’re deleting something, so just remove that loop, and echo(). [ad_2] solved php mysql_fetch_array() error [duplicate]
[ad_1] You can try like following using GROUP BY and UNION ALL. select count(*) CT,Mark from TableName group by Mark union all select Count(*), ‘A+B’ as mark from TableName where mark in(‘A’,’B’) UNION ALL select Count(*), ‘A+C’ as mark from TableName where mark in(‘A’,’C’) union all select Count(*), ‘B+C’ as mark from TableName where mark … Read more
[ad_1] you did not open your connections. try it by adding this myconn.open(); before this line MySqlDataAdapter mydata = new MySqlDataAdapter(strSQL, myconn); 1 [ad_2] solved How to retrieve data from MySQL DB to GridView in ASP
[ad_1] The correct way to avoid SQL injection attacks, no matter which database you use, is to separate the data from SQL, so that data stays data and will never be interpreted as commands by the SQL parser. It is possible to create an SQL statement with correctly formatted data parts, but if you don’t … Read more
[ad_1] check this : http://sqlfiddle.com/#!2/d07965/20 Use this query. Only thing you are missing is equality condition. : select * from rooms A left join reservations B on A.id = B.room_id and B.reservation_date=”2014-01-11″ and B.start_period_id <= 11 and B.end_period_id >= 11 where B.room_id is null; Regards, Mansi [ad_2] solved Please help querying for room’s availability [closed]
[ad_1] Mysql won’t understand if ..else shell syntax and so you will need to execute mysql within each if, else block with -e for execution e.g: … elseif [ “$(date +%m)” -eq 2 ] then mysql –login-path=local -e “use testdb;select COUNT(id) from xxx where app_id =’ABC’ and date(creation_date) between ‘$(date +%F -d “tomorrow -28 days”)’ … Read more
[ad_1] This question does not really belong here, but I’ll answer it for the sake of closing the question without bothering moderators. // mysql query is executed $images = mysql_query(“Select URL from images where Category = ‘Management’ “); // empty array initialized $imagerow = Array(); // while there are results of the executed mysql query … Read more
[ad_1] implementing automatic deletion of a (related) row of record in PartyEvent table, when a row from the Client table is deleted [ad_2] solved implementing automatic deletion of a (related) row of record in PartyEvent table, when a row from the Client table is deleted
[ad_1] You can do this with either a switch statement or an elseif: if ($row[‘rank’] == 1 |){ echo ‘Administrator’; } elseif ($row[‘rank’] == 2){ echo ‘Moderador’; } elseif ($row[‘rank’] == 3) { echo ‘Helper’; }else{ echo “Not Ranked”; } OR switch ($row[‘rank’]) { case 1: echo ‘Administrator’; break; case 2: echo ‘Moderator’; break; case … Read more
[ad_1] The IN operator allows you to specify multiple values in a WHERE clause. Try this query : SELECT * FROM table WHERE column in ($var); Reference-1 0 [ad_2] solved SELECT * FROM table WHERE column = 1,2,3,4 [duplicate]
[ad_1] The $data array contains multiple associative arrays (one for each record returned). If you want just the values for high for each record in one array and just the values for low in another the result set, you could do: <?php $high = array_column($data, ‘high’); $low = array_column($data, ‘low’); ?> 1 [ad_2] solved Php … Read more
[ad_1] If you are using raw queries, then you just need to merge the data. Something like this should work, def merge_order_data_and_detail(orders, details): “””Group details by order_id and merge it in orders.””” # create dictionary key:order_id value:[order_detail_data] dic = {} for d in details: if d[‘order_id’] not in dic: dic[d[‘order_id’]] = [] dic[d[‘order_id’]].append(d) # iterate … Read more