[ad_1] (‘The SQL contains 0 parameter markers, but 50 parameters were supplied’, ‘HY000’) or TypeError: ‘tuple’ object is not callable [ad_2] solved (‘The SQL contains 0 parameter markers, but 50 parameters were supplied’, ‘HY000’) or TypeError: ‘tuple’ object is not callable
[ad_1] Easiest way of creating dynamic dropdown is by using jquery inside the head tag. Give onchange() event and guide the data to another page using jquery code, and then link 2 dropdowns. The code I did is like this, which I felt is the easiest way for dynamic dropdowns. jquery which I included is … Read more
[ad_1] Keep space between your concatenation, $ok = 1; $sql = “UPDATE users SET fn = :first, ln = :last”; if($ok == 1){ $sql .= “, phone = :phone “; } $sql .= ” WHERE users.id = :id”; 0 [ad_2] solved adding php if condition in mysql query
[ad_1] Yes, It is possible to reduce query time using view because it have clustered index assigned and they’ll store temporary result that can speed up resulting queries. 2 [ad_2] solved MySQL View is faster or not for querying from DB that containd 40 million data [closed]
[ad_1] Try this: var emailpat = /^[^@]+@[^@]+\.[^@\.]{2,}$/; Email addresses should have just one @-sign, and that can’t be the first character. After the @ you’ll need at least one dot followed by 2 or more letters. And yes, this also accepts email addresses that are not valid. If you want to be sure that the … Read more
[ad_1] Given the code you’ve posted, here’s how I’d handle this. First, I’d create an associative lookup array whose keys are the column names and whose values are the corresponding point values; it would look something like this: $pointVals = array(’email1′ => 2, ’email2′ => 5, ’email3′ => 2, … ); You can generate this … Read more
[ad_1] you can try this SELECT Department.DeptName, COUNT(Employee.FName) AS EmpCount FROM Employee INNER JOIN Department ON Employee.DeptId = Department.ID GROUP BY Department.DeptName order by EmpCount 2 [ad_2] solved SQL query to list department names in descending order of employee count
[ad_1] mysql_real_escape_string() needs an active connection to the MySQL server and will initiate one with the default data from the php.ini configuration if there is none. Do not use this function without first connecting to the database. Also, do not use the mysql_* functions. They are deprecated and will be removed from PHP. 2 [ad_2] … Read more
[ad_1] Your approach is wrong. Your CodeIgniter controller needs to run a curl request to the blog’s XML-RPC API endpoint and process the response, then display it as you need to. A second option is to just use an iFrame on the page, although iFrames were outlawed at some point in 2005. 0 [ad_2] solved … Read more
[ad_1] You’re using standard quotes instead of backticks for escaping the MySql reserved word KEYS. Change the table name to any non-reserved word so that the quotes can be removed. 1 [ad_2] solved SQL syntax error in “insert into ‘keys'(a,b,c,d,e) values(?,?,?,?,?)” [closed]
[ad_1] SELECT MIN(a.ID) ID, a.name, SUM(b.Price) Price FROM table1 a INNER JOIN table2 b ON a.PID = b.PID GROUP BY a.Name SQLFiddle Demo OUTPUT ╔════╦══════╦═══════╗ ║ ID ║ NAME ║ PRICE ║ ╠════╬══════╬═══════╣ ║ 1 ║ ram ║ 4333 ║ ║ 2 ║ rani ║ 2000 ║ ╚════╩══════╩═══════╝ [ad_2] solved get the total values of … Read more
[ad_1] I’ve mocked up some table data to test my query. WHERE clauses must be positioned after JOINs. You are also a little ambiguous about the comparison of COUNT AND 5 — if you want more than 5 then >5, if you want 5 or more then >=5. SQL: (SQLFiddle Demo) SELECT a.user_id,a.username,COUNT(b.user_id) FROM users … Read more
[ad_1] Yes, it’s possible to access the web server from an external network, depending on your current network configuration. There are two simple solutions I think would suit you. Configure your firewall if needed, enable port forwarding in your router settings to forward port 80 to the internal IP of the machine running your XAMPP-server. … Read more
[ad_1] You only need one function, run a join in your query SELECT customer_id, name FROM customer_ids INNER JOIN customers ON customer_ids.customer_identify = customers.identify This should get the required fields then jun run your loop normally 0 [ad_2] solved mysql_fetch_array -> 2 mysql queries
[ad_1] You could use two different database handles. As a general rule mixing MySQL and MySQLi in the same code is a bad idea and the MySQL code will probably get deprecated in a few years. 1 [ad_2] solved Is it Possible to have two database connection in a single page in php? [closed]