[ad_1] I think result may vary depending on which processor and which language you’re using. This because float numbers (in general) are stored with a number of bits that try to represent that fractional number, but there can be some (very little) difference. So when you do (d1-d2) you probably get a number really close … Read more
[ad_1] My solutions was accepted by interview street. Firstly, my solutions wasn’t accepted, but after saw @Reinardus Surya Pradhit post, i realized, if pair (x, y) will be count twice, so i change it a litter bit and got success I will not post my solution here, but i can tell you the test case … Read more
[ad_1] A simple test for whether some integer N is a Fibonacci number is as follows: N is a Fibonacci number iff either (5 * n^2 + 4) or (5 * n^2 – 4) is a square number. See here for the ingenious proof (page 417): http://www.fq.math.ca/Scanned/10-4/advanced10-4.pdf If it turns out that N is not … Read more
[ad_1] What is the total count of digits from 1 to N such that number of odd digits in the number is even and no of even digits are odd? [ad_2] solved What is the total count of digits from 1 to N such that number of odd digits in the number is even and … Read more
[ad_1] //Example with mutliple coordinates before creating an arc. AREA DEFINED AS 133830N1450807E TO 132836N1444449E TO 133043N1443814E TO 133515N1443710E THEN CLOCKWISE ON A 15.3 NM ARC CENTERED ON 133416N1445256E TO THE POINT OF ORIGIN //Abbreviation // a // b // m(midangle) (cx,cy,ax,ay,bx,by) // x(lat) // y(long) //Xc=latitude provided in text for center point //Yc=longitude provided … Read more
[ad_1] [EDIT] So based on you’re edit i thought this solution. Since you don’t specify any programming language i’ll use some c-like functional programming. I’ll leave you the work of transforming it to object oriented if you need it. Input: Global maxtrix that starts in M[0,0] and ends in M[100’000, 100’000] (Note that, to make … Read more
[ad_1] You can reformulate the question y = sqrt(x) as to find the value for y such that y*y – x equals zero. The easiest way to solve that equation is by doing a bisection on y (http://en.wikipedia.org/wiki/Bisection_method) between 0 and x (because 0 <= sqrt(x) <= x for all real numbers x where x … Read more
[ad_1] To get a column number (or, more precisely, “left 3 or right 3”) subtract 1 and do a % modulus operator: (value-1) % 6. The result will be 0..2 (or “left column”) or 3..5 (so “right column”). 1 [ad_2] solved how to check number in range with n level
[ad_1] In the line $open = fopen(“http://quote.yahoo.com/d/quotes.csv?s=$symbol&f=sl1d1t1c1ohgv&e=.csv”, “r”); You need to substitute the actual symbol, not leave it as a string in the query. Maybe something like this: $open = fopen(“http://quote.yahoo.com/d/quotes.csv?s=”.$symbol.”&f=sl1d1t1c1ohgv&e=.csv”, “r”); to concatenate the symbol will help. If you have an invalid request, you are probably looking at garbage. Also – you need to … Read more
[ad_1] public static int addZeros(int valueToAddZeros, int valueToCompare){ while(String.valueOf(valueToCompare).length() > String.valueOf(valueToAddZeros).length()){ valueToAddZeros = valueToAddZeros * 10; } return valueToAddZeros; } 1 [ad_2] solved java – How to add zeros to an int until this int lenght equals the int2 lenght? [duplicate]
[ad_1] So you have power of 2 operations which can be easily converted to bit operations… no bigint lib is needed for such triviality. Let assume you got number const int n=1000000000; // number size in bytes BYTE x[n]; // number bytes let num[0] be LSW (least signifficant Word) So the operations involved are: mod: … Read more
[ad_1] How about a_n = (-1)^n / sqrt(n) (source) For positive a_n there is no such sequence. Next time, you might want to ask at math.SE. [ad_2] solved sequence whose series is convergent, but square is not convergent [closed]
[ad_1] Have you taken algebra? PrValue = (Pa * (1-Math.pow(1+IntRate, – (Period*PPay))))/IntRate 1 [ad_2] solved Reversing a math formula [closed]
[ad_1] If you are using LWJGL you can also use JOML, in which case the following is probably what you might want: import org.joml.*; public class CubePositions { public static void main(String[] args) { /* Cuboid center position */ float px = 10, py = 0, pz = 0; /* Euler angles around x, y … Read more
[ad_1] mkasberg provided the solution: $in = 72; $out = array(); $a = array_reverse(str_split((string)decbin($in))); foreach($a as $k => $v){ if ($v != “0”) array_push($out, pow(2,$k)); } 0 [ad_2] solved How do I return an integer array the sum of which equals to a given number in php? [closed]