[ad_1] You can do it like this: $(“.layout_theme”).click(function(){ $(“.file_uploader”).animate({ left: $(this).offset().left – parseInt($(this).css(“margin-left”)) + “px”, top: $(this).offset().top + $(this).height() – parseInt($(this).css(“margin-top”)) + “px” }) }); Check it your here: http://jsfiddle.net/zd78e8a3/1/ 1 [ad_2] solved Moving div on click [closed]
[ad_1] var url = videoSpan.data(“vimeoid”); var thisVideo = ‘<span class=”video” data=”‘ + url + ‘”></span>’; 0 [ad_2] solved How to concatenate and use a variable in a variable in jQuery?
[ad_1] You can use hidden inputs: <input type=”hidden” name=”image_ids[]” value=”1″> <input type=”hidden” name=”image_ids[]” value=”2″> <input type=”hidden” name=”image_ids[]” value=”3″> Just create a new hidden input for each image id, with the same name image_ids[]. Note that when you append [] to the name of various input fields, these values are submitted as an array, in this … Read more
[ad_1] Try this : put id for anchor tag <a id=”anchor1″ href=”https://stackoverflow.com/questions/25931155/site.com/register.php?mid=username&mode=bn&bid=1″> use below javascript <script> var href = document.getElementById(‘anchor1’).href; //get index of ? var indexStart = href.indexOf(‘?’); var indexLast = href.length; //get href from ? upto total length var params = href.substring(indexStart+1, indexLast); //get tokens with seperator as ‘&’ and iterate it var paramsArray … Read more
[ad_1] In your CSS you’ve #Main-button { width:200px; } but the JS is adding dynamic inline style based on content. So it’s having style attribute. So in terms of CSS specificity their CSS beats you. You must use !important in your rule to avoid overriding of your CSS. #Main-button { width:200px !important; } 0 [ad_2] … Read more
[ad_1] Javascript is client side langauge and jquery is a javascript library. Client side language has no power to access server side funcationality. So obviously that code will return the client side window size. From Wiki Client-side scripting generally refers to the class of computer programs on the web that are executed client-side, by the … Read more
[ad_1] Notice: Undefined variable: message in /Users/kobigo/Sites/yedikitamuhendislik.com/sendEmail.php on line 61 Look at what appears to be line 61: $message .= “Gönd.: ” . $name . “<br />”; You’re trying to append to $message, but you never defined it in the first place. You can append to it after it’s been defined, but on this first … Read more
[ad_1] ID of an element must be unique, so need to use class to group similar elements, also in the click handler you need to find the title element which is a descendant of the clicked li jQuery(‘#restaurant-menu-content-tab’).on(‘click’, ‘#res-menu-filters li’, function(e) { var value = jQuery(this).find(‘.menu-extend-title’).text(); jQuery(‘#menu-title-layout-text’).text(value); return false; }); <script src=”https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js”></script> <div id=”restaurant-menu-content-tab”> <div … Read more
[ad_1] Try changing famous each function to this: $(“.tabs .nieuwe_offerte_table tbody tr td a.product_toevoegen”).slice(start_week-1, eind_week).append(product); 4 [ad_2] solved Jquery each only adds the first elements
[ad_1] Let’s break this into bare parts, and fix the indentation. Then use some static analysis to compact the if statements. <!–script for changing Number of Columns–> $(window).load(function(){ function oneColumnClick() { $(‘.IH_pINameRow’).removeClass(“floatLeft “); $(‘.IH_pINameRow’).addClass(“floatNone “); $(‘.odd’).removeClass(“leftMargin”); $(‘.even’).removeClass(“rightMargin “); $(‘.pI_nameText’).removeClass(“textAlignLeft textAlignRight”); $(‘.pI_nameText’).css(‘font-size’, ‘2em’); $(‘.pI_nameText’).addClass(“1col”); $(‘.pI_nameText’).removeClass(“2col”); $(‘label.twoColumn’).css(‘background-position’, ‘-104px -52px’); $(‘label.oneColumn’).css(‘background-position’, ‘-104px -26px’); } function twoColumnClick() { $(‘.IH_pINameRow’).removeClass(“floatNone … Read more
[ad_1] This website is for people that intend to program or already do, I don’t believe asking for code is allowed. Anyways, you might be interested on Google Forms or Surveymonkey, two of the countless survey serving services for non-programmers. If you do intend to learn HTML and Javascript, you’ll definitely need more time, and … Read more
[ad_1] you forgot to concatinate the last string ”, so youre missing a “+” $(‘.customfield’).val(‘<?php echo $userdata[“id”] ?>,clicks,’+amount+’,’+cPrice+”); though you dont need the last string bit cause its empty anyway so you can just $(‘.customfield’).val(‘<?php echo $userdata[“id”] ?>,clicks,’+amount+’,’+cPrice); and you can concatinate as many variables as you want to in the docs you can read … Read more
[ad_1] The escaped quotes match each other in the HTML string that you’re creating. The quotes are not “surrounding” +i+. They’re being used to end the string that begins with “<p id=\”element” and to begin the next string: “\”>Hello world, …” This is concatenating i between these two strings. So if i contains 0, the … Read more
[ad_1] Change your jQuery selector to $(‘.selectedoptionselect’) The value of the select will be whatever option is selected. [ad_2] solved Create array with values of multiple select dropdown options [closed]
[ad_1] If you’re using the Javascript SDK to publish stories, show the content in the callback response when a user shares content successfully: FB.ui( { method: ‘feed’, name: ‘Google’, link: ‘http://www.google.com/’, picture: ‘http://google.com/xyz.jpg’, caption: ‘Google Logo’, description: ‘Search away’ }, function(response) { if (response && response.post_id) { // YOUR CODE GOES HERE // e.g. $(“#some_div”).show(); … Read more