It seems, your original photo contains EXIF metadata records. Among others, it can contain additional instructions how to process the image before being shown. Some apps/SDKs do respect that instructions, others silently ignore EXIF – this is why you can receive such thing as mirroring etc. EXIF orientation values There are 8 possible EXIF orientation … Read more
JPEG files are not text files. You need to Read and write bytes instead. ie: DirectoryInfo d = new DirectoryInfo(@”E:\New folder (2)”); FileInfo[] Files = d.GetFiles(); foreach (FileInfo file in Files) { string changed = Path.ChangeExtension(file.FullName, “jpg”); File.Copy(file.FullName, changed); } Of course file themselves should be JPEG for this to work. 4 solved Changing the … Read more
You’d better use other frameworks other than OpenCV. OpenCV is extremely heavy for this kind of job. It’s mainly focused on image processing. Maybe you can use OpenImageIO, freeimage or other libs. You can refer to these posts: Reading an image file in C/C++ https://products.fileformat.com/image/cpp/openimageio solved How to build opencv that only support decode jpeg?
$filename=”437-1.jpg.JPG”; $size = getimagesize($filename); print_r($size); if ($size) { echo ‘Width:’ . $size[0] . ‘px <br>’; echo ‘Height:’ . $size[1] . ‘px <br>’; } But first spend some time and learn PHP syntax. 2 solved PHP Parse JPEG File and retrieve image dimensons