Based on the link you’ve shared, if you want a popup over any desktop application through the browser, use the W3C Notification API. For example window.onload = function () { if (Notification.permission !== “granted”) Notification.requestPermission(); }; function notifyMe() { if (!Notification) { alert(‘Desktop notifications not available in your browser. Try Chromium.’); return; } if (Notification.permission … Read more
It seems like you want to encode your PHP array to JSON. Use json_encode() for that. json_encode($array); Returns a string containing the JSON representation of value. solved How to change data php to javascript json [closed]
I would add a common class to all divs and wrap them in a div. Try: var len = $(“#container”).find(“.section”).length; setInterval(function(){ var current = $(“.section:visible”); var active = $(current).index(); var next; if(active == len-1){ next = 0; } else{ next = active+1; } $(current).hide(); $(“#container .section:eq(“+next+”)”).fadeIn(); },1000); DEMO here. 4 solved I need to fadein … Read more
Try this: $(“html, body”).animate({scrollTop: $(“body”).height()*0.2},2000); 1 solved How to scroll at 20% of the html page? [closed]
I see you’re trying to link to a javascript file from a javascript file. You should totally drop that and try jQuery, a lightweight free library for Javascript. With that, you can just do it like this: $.getScript(“myscript.js”,function(){ alert(“script has been loaded!”) }); Alternatively, you can append scripts to the end of your body, but … Read more
You can use the download attribute to force download and JS to automatically click that link. document.getElementById(‘download’).click() <a href=”https://scontent.cdninstagram.com/t51.2885-15/s640x640/sh0.08/e35/23279358_143343893084349_1681002671546302464_n.jpg” download id=”download”>Download begins</a> 3 solved How can I download pictures from a URL to a local computer without asking permission?
Try this: <td id=”myTd”><span class=”dott active green”></span> Firstname Lastname</td> $(‘#myTd’).find(‘span’).remove(); solved Remove HTML element from string
These links may help. Submit a form with Ajax and jQuery: http://net.tutsplus.com/tutorials/javascript-ajax/submit-a-form-without-page-refresh-using-jquery/ Validate a form: http://jqueryvalidation.org solved Submit a Form with Validations using AJAX and PHP [closed]
Generally you should do it the following way: Attach an event to the button just as @Marc B suggested In the function for the event do a jQuery.ajax request, sending the users name (type to POST would be a good idea and the users name inside data) On the server create a PHP file (for … Read more
nice question! They way you could do something like that would be.. to try and check what is your url – in this case is: header(“Location: ../Home.php?signup=success”); … and basically see if it contains the keyword “signup=success”. To do this, you need $url=”http://” . $_SERVER[‘SERVER_NAME’] . $_SERVER[‘REQUEST_URI’]; if (strpos($url,’signup=success’) !== false) { echo ‘Thank you … Read more
in c#, you can do this string s = “UK”; int counter = 0; if (counter < 10000) result = s + counter++.ToString().PadLeft(4, ‘0’); else result = s + counter++.ToString(); Output: UK0000,UK0001,UK0002…… solved Auto Increment the number [closed]
Breaking down the expression into the correct order of operations, you have: (!(+[])) + (!(+[])) First things first, [] is cast to a number by +, which results in 0. Don’t ask me why, it just does :p Probably buried in the specification somewhere. !0 is simply true So you end up with true + … Read more
// will match http://localhost only: $(‘a[href=”http://localhost”]’).find(‘img’).attr(‘alt’); // will match links hreffing to URLs starting with http://localhost $(‘a[href^=”http://localhost”]’).find(‘img’).attr(‘alt’); 6 solved Get img alt which parent a’s href is something [closed]
There are two syntax errors in your code: function isEven(value) { //value = Number(value); if (value%2 == 0) // no parens here is allowed so no syntax error return true; else return false; } function testCondition() { // ^^ missing parens here if (isEven(n)) { // ^ ——- ^ — and here } else { … Read more
https://www.google.com/webmasters/tools/mobile-friendly/ You can use this to test mobile friendliness. Here are a few more websites to help: https://validator.w3.org/mobile/ https://validator.w3.org/mobile/ http://mobiletest.me/ – This one lets you choose a device to emulate the browser solved Check my site in different browser version for mobile friendliness