Just use Pandas to convert your lists (income and Expenses) into Dataframes, merge them (in this case it’s basically an inner join on Year and Month) and then convert the Dataframe you get into a list of lists. df1 = pd.DataFrame(income, columns=[“Year”, “Month”, “X”]) df2 = pd.DataFrame(Expenses, columns=[“Year”, “Month”, “Y”]) joined = df1.merge(df2, on=[“Year”, “Month”]).values.tolist() … Read more
SELECT strPath from path INNERJOIN filelinkpath ON path.idPath = filelinkpath.idPath 2 solved Mysql INNER JOIN with multiple IDs and Tables
You can use inner join to get price for each product in orders table: Select o.customer_id, p.product_id, o.quantity, p.price from PRICES p inner join ORDERS o on p.product_id=o.product_id solved How to join each order with its price? [closed]
List of critical model per store and main resources in stock if any or cero select a.sloc, a.model, a.stock critical, isnull(b.stock,0) ‘Main Resources’ from stock a left join stock b on a.model=b.model and b.sloc=”Main” where a.stock<5 For the last part of your request, I’m not sure what is needed for a new opened store. EDIT … Read more
Move the SAS syntax to the SAS side of the query. You also had an extra comma in the middle of the FROM clause. Note if you get in the habit of putting the commas (or any other continuation characters) at the beginning of the line instead of the end they will be easier for … Read more
This query might help except ‘terms’ field bcoz there is no mapping from contract table to any other tables. select title,salary,descr,req,duties, county,name as comapny_name,job_location from job j join job_location jl on j.jid=jl.jid join location l on jl.lid=l.lid join job_company jc on jc.cid=j.jid join company c on c.cid=jc.cid 2 solved How to perform mysql joins in … Read more
The solution is to join on the common fields you already indentified: SELECT item_details.* FROM item_details JOIN item_detail_addon USING(Item_Details_Id) JOIN item_addon USING(Item_Addon_Id) If some fields on a table have the same name of a field on another table, you can get both by using aliases: SELECT table1.field1 as table1_field1 , table2.field1 as table2_field1 [ .. … Read more
Presumably, you have more orders than you have employees. Hence, one employee is on many orders. When you run: select e.firstname from employees e inner join orders o on e.employeeid = o.employeeid; Then you are getting a list of all first names — so one employee name is going to be repeated, once per each … Read more