Is this what you were looking for? window.onload = timeInfo(“automatically on load,”); function timeInfo(message) { console.log(message + ” called function”); } document.getElementById(“liked”).addEventListener(“click”, function() { timeInfo(“clicking button”); }); <div class=”author_other_button”> <button id=”liked” class=”likebuttonliked”>მოწონებულია</button> </div> 1 solved run button working, when website will be load [closed]
You are calling whole logic in onchange, you got wrong double qoutes (not sure but may be causing issue). Also document.getElementByid should be document.getElementById (see I in capital for Id) You should write a separate Javascript function and call it on change event of input. So change below line <br><input list=”Service” name=”Service” value=”** Select **” … Read more
Unfortunately you may want to think about redoing your site using twitter bootstrap and not your original css. I also noticed that your css does not use any of the classes used in bootstrap which means that your html will need major changes in order to use bootstrap’s framework. So with that said you may … Read more
In the future, try to give this a shot for yourself and ask more specific questions. I don’t see why you don’t want to use a service if you’re not writing it anyway. However, since you are, here’s my suggestion. Javascript: var banners = [ { “img”: “tnl-banner-steve-jobs-01.png”, “url”: “http://news.stanford.edu/news/2005/june15/jobs-061505.html”, “weight”: 1 }, { “img”: … Read more
Use a function and initialize it at the end of your script and keep the DOM as @AnoopJoshi suggested <button id = “button1″ style=”display:none” >Click me!</button> and script would be function init(){ document.getElementById(“button1”).style.display = ‘block’; } init(); solved Show button only if Javascript loads
Use this : $(“#element id”).removeClass(); Calling removeClass with no parameters will remove all of the item’s classes. You can also use (but is not necessarily recommended, the correct way is the one above): $(“#element id”).removeAttr(‘class’); $(“#element id”).attr(‘class’, ”); $(‘#element id’)[0].className=””; If you didn’t want to use jquery you can use java script: document.getElementById(‘item’).className=””; 2 solved … Read more
This kind of component is called range in the context of a HTML form. There is a demo available at W3schools’ HTML Input Types page. It can also be referred to as a slider in case of JQuery ui slider component for example. In any case, both slider or range are quite self-explainatory terms that … Read more
I’m confused. The question title refers to compiling CSS/SCSS, the question refers to compiling PHP/HTML. Since you tagged the question with sass, I’m assuming you’re trying to ask why we need to compile SASS to CSS, instead of just being able to include the SASS file into our projects? If that is your question, it’s … Read more
This map created using SVG. Here is a website with SVG’s maps. https://www.amcharts.com/svg-maps/ solved How to create a map like the one that’s there on ikman.lk [closed]
You are missing . at selector at body = el.querySelectorAll(‘.fixedTable-body’); sidebar = el.querySelectorAll(‘.fixedTable-sidebar table’); header = el.querySelectorAll(‘.fixedTable-header table’); 2 solved can anyone tell me the javascript equalent for this [closed]
This is a very tricky question indeed. I’ll give it a shot, but mind you I’m barely going to scratch the surface with this. Disclaimer: What I’ve written now, especially considering the speed with which the web is moving forward/changing (new W3C standards, new frameworks, new levels of abstraction over the same old programming principles), … Read more
Without more information we are left to guess at what would help your situation. In order to process something like this, you’re most likely going to need a stronger, more processed language to work alongside HTML such as PHP, .NET, JavaScript or one of the many other choices. Your <form>‘s processing will need to pass … Read more
You could also use the :not() selector based on the OP’s original premise – (I’m assuming that ‘cool’ and ‘hot’ are classes in this example) $(‘.cool:not(.hot)’).css({‘display’:’none’}); You could also use the .not() method – $(‘.cool’).not(‘.hot’).css({‘display’:’none’}); solved If a element hasClass then display:none;
You can try after or before Pseudo Elements to make this. [Demo] .pillar:after, .pillar:before { position: absolute; content: ”; height: 350px; width: 64px; top: 16px; left: 70px; background-image: url(http://www.indonesia.travel/public/media/images/upload/poi/Danau%20Segara%20Anak%20-%20Gallery.jpg); } 3 solved How can make white line effect on image [closed]
You have a site where you load jQuery UI, but that is dependent on jQuery. Make sure you include that on the page before jQuery UI. <script src=”https://ajax.googleapis.com/ajax/libs/jquery/3.2.1/jquery.min.js”></script> solved Whats wrong with this HTML