[Solved] How to design Grids for sudoku in Android [closed]
Here is a sample source code for sudoku from the book hello android. 0 solved How to design Grids for sudoku in Android [closed]
Here is a sample source code for sudoku from the book hello android. 0 solved How to design Grids for sudoku in Android [closed]
This is a very interesting problem. The problem, as you so rightly indicate, is in the JavaScript file. The first problem I can see is the way you are setting div.style.gridColumnStart in the initTile function (also known as method). grid.style.gridColumnStart is not a function, but a setting (also known as property), so you should just … Read more
Since your post is semi vague I will do my best to just describe… I use the jQueryUI Draggable/Droppable functions. With this you can make your own grid as you see fit and tie in the jQueryUI to get the drag n’ drop you desire. 2 solved Drag ‘n Drop with Grid [closed]
According to your question, you see 3 classes used, there are 4 basic classes – col-lg-x , 2. col-md-x , 3. col-sm-x , 4. col-xs-x. -lg –> Large desktops. -md –> laptops/desktops. -sm –> tablets. -xs –> mobile screens. And “-x” stands for numeric value of width in terms of blocks, ranging between 1 and … Read more
In the 2×2 case you have 6 possible ways you say. (So I infer from that that you actually move from grid-point to grid-point rather than from cell to cell): (r,r,d,d), (r,d,r,d), (r,d,d,r), (d,r,d,r), (d,d,r,r), (d,r,r,d). Note that we always have 2 ‘d’s and 2 ‘r’s. And we always have 4 moves (_ , _, … Read more
You can do that by making your “existing grid” a separate UserControl. First, you need to add a UserControl via [Add]->[User Control…]->[User Control (WPF)]. Next, put your “existing grid” inside the added UserControl. YourExistingGridControl.xaml <UserControl x:Class=”Your.Namespace.YourExistingGridControl”> <Grid> … YOUR EMPTY GRID WITH ALL THE COLUMNS, ETC. … </Grid> </UserControl> Now, you can create as many … Read more