Read the file sequentially – thats the easiest route. Then randomly shuffle the collection. Actually, another question. Could you use math.random() to look at the lines of the text file and if, lets say, the line 5 comes up then you remove it from the parameters you set for math.random()? It would pick from 0-9 … Read more
Reads & prints the content public static void main(String[] args) { List<String> li=new TestClass().textFiles(“your Directory”); for(String s:li){ try(BufferedReader br = new BufferedReader(new FileReader(s))) { StringBuilder sb = new StringBuilder(); String line = br.readLine(); while (line != null) { sb.append(line); sb.append(System.lineSeparator()); line = br.readLine(); } String everything = sb.toString(); System.out.println(everything); } catch (IOException e) { e.printStackTrace(); … Read more
This is partly finished code, to show you the idea what has to be done, but it may have some flaws, it uses Google Guava – http://code.google.com/p/guava-libraries/ import java.io.File; import java.io.IOException; import java.nio.charset.Charset; import java.util.ArrayList; import java.util.List; import com.google.common.io.Files; public class LinesDeleter { private static boolean between; public static void main(String[] args) throws IOException { … Read more
Your program is not “stuck”, it is waiting for you to enter the “user input” (again). You keep calling returnUserInput() inside the loop, and it calls getUserInput(), which will wait for you to type (another) string and press Enter. As for your code, don’t declare line as a field. It should be a local variable. … Read more
Ok, I think converting string into Integer and then typecasting it to double is causing the error. Why don’t you just convert the string to double. Also you must trim the line while reading it to avoid any spaces. String holderStr = br.readLine().trim(); System.out.println(holderStr); totalBalNum = Double.parseDouble(holderStr); 2 solved NumberFormatException error from reading a file