[Solved] Unable to print recursive fibonacci sequence correctly
if (n == 0) not if (n=0) check your syntax careful. solved Unable to print recursive fibonacci sequence correctly
if (n == 0) not if (n=0) check your syntax careful. solved Unable to print recursive fibonacci sequence correctly
On your system, long is 32 bits. The largest positive integer it can hold is 4294967295. But 1836311903 + 2971215073 = 4807526976, which is larger, so it overflowed and you got 512559680 (which is 4807526976 – 4294967296). If you want to go past the 47th Fibonacci number, you’ll need a larger datatype or do multi-precision … Read more
As mentioned in the comment above your program do its job and perfectly described the Fibonacci sequence. Here I implement the recursive version and then compare the result with your implementation (explicit form). import math def staircase(n): term_a = ((1 + math.sqrt(5)) / 2) ** n term_b = ((1 – math.sqrt(5)) / 2) ** n … Read more
public static int[] FibLength(int l) { int fib[] = new int[l]; fib[0] = 1; fib[1] = 1; for (int i=2; i<fib.length; i++) fib[i] = fib[i-1] + fib[i-2]; return fib; } solved Fibonacci int[] sequence [closed]
Optimization comes usually comes in steps. You start off with the obvious solution. iterate_fibs_mod10; remove_odds(n); Then you realize that you really only need the expensive modulus once for one element. nth_fib(remove_odds(n))%10; Then you realize you don’t need to remove the nodes if you can deterministically find which one would have remained. nth_fib(as_if_remove_odds(n))%10; Then you figure … Read more
When in doubt, just break it down. The tree flow is actually counter-intuitive to the actual control flow, but once you understand the sequence of calls, it becomes clearer. The thing to understand here is that you keep breaking down a larger computation to a sum of smaller computations, and you stop when you hit … Read more
The following Python 3.0 script will work: def f(i): a, b = 0, 1 for i in range(i): a, b = b, a + b return a print(f(0)) print(f(1)) print(f(2)) print(f(3)) print(f(1000)) Giving you: 0 1 1 2 and 43466557686937456435688527675040625802564660517371780402481729089536555417949051890403879840079255169295922593080322634775209689623239873322471161642996440906533187938298969649928516003704476137795166849228875 3 solved Calculate the function of f(i) [closed]
I am afraid you need to really clean up your code.The following is absolutely wrong in C. (int i = 0; i < n; i++) I am sure you intend a for loop here.But who knows what you had in mind? Then you have enclosed a solitary else in the if block in Fibonacci().There are … Read more
You can combine the two examples, as such: Take the DynamicArrayOfInt class, and add the main method of the Fibonacci class. Insert a new statement at the beginning of the main method instantiating a DynamicArrayOfInt object, as such: DynamicArrayOfInt arr = new DynamicArrayOfInt(); Replace every instance of numbers[x] with arr.get(x), and instances of numbers[x] = … Read more
There are many issues with your code. And you should first learn and try as much as you can on your own. I am also a beginner so I know what you are thinking. For some quick edits to make it workable: n1 = 0 n2 = 1 n3 = 0 for i in range(10): … Read more
Do it like you asked for the starting number: number_of_outputs = int( raw_input(‘Enter the number of outputs: ‘)) #Your code goes here for i in range(number_of_ouputs): #More code goes here 0 solved range as input in python
First you should check that you understand the definition of the Fibonacci numbers. By definition, the first two Fibonacci numbers are 0 and 1, and each remaining number is the sum of the previous two. Some sources omit the initial 0, instead beginning the sequence with two 1s. You need two variables to remember the … Read more
To give you a small hint without doing all the work for you (as this seems to be some task for school, college, or university), here’s how a Fibonacci number is defined: f(0) = 0; f(1) = 1; f(n) = f(n – 1) + f(n – 2); So in C++ this could be written like … Read more