[Solved] minimal JS sources for wiping out the whole DOM
document.body.innerHTML = “” document.head.innerHTML=”” …but why? 2 solved minimal JS sources for wiping out the whole DOM
document.body.innerHTML = “” document.head.innerHTML=”” …but why? 2 solved minimal JS sources for wiping out the whole DOM
I have found couple of issues here. You have two form tags which is un-necessary and the form tags needs to have a name and id. Atleast name attribute must be there. Check the following fiddle http://jsfiddle.net/ayyadurai/3Ru9T/ <form name=”form1″ id=”form1″> <input type=”button” id=”button” value=”click” onClick=”what()” /> <input type=”text” id=”text” value=”hey” /> </form> var button = … Read more
CSS doesn’t have direct equivalents for relative values of the obsolete size attribute. For font sizes relative to the font size of the parent element, use a relative unit such as em, % or ex. 1 solved What is replacement for in CSS?
You can do like this, swap the elements order in the parent node. var div1 = document.getElementsByClassName(“div1”)[0]; var div2 = document.getElementsByClassName(“div2”)[0]; div2.parentNode.insertBefore(div2, div1); 0 solved Can i change HTML structure with javascript? [closed]
You can use XPath with an expression like //Book[ListOfBookUser/BookUser]: var xmlMarkup = `<ListOfBook> <Book> <Id>ACIA-11QWTKX</Id> <ListOfBookUser recordcount=”0″ lastpage=”true”> </ListOfBookUser> </Book> <Book> <Id>ACIA-ANC0CC</Id> <ListOfBookUser recordcount=”1″ lastpage=”true”> <BookUser> <BookId>ACIA-ANC0CC</BookId> <BookName>TKSP_GLOBAL</BookName> </BookUser> </ListOfBookUser> </Book> <Book> <Id>ACIA-ANC0CF</Id> <ListOfBookUser recordcount=”0″ lastpage=”true”> </ListOfBookUser> </Book> <Book> <Id>ACIA-EUMCH5</Id> <ListOfBookUser recordcount=”1″ lastpage=”true”> <BookUser> <BookId>ACIA-EUMCH5</BookId> <BookName>TKSP_MADRID_CENTRO_SUR</BookName> </BookUser> </ListOfBookUser> </Book> </ListOfBook>`; var xmlDoc = new DOMParser().parseFromString(xmlMarkup, … Read more
this.tooltip = this.renderer.createElement(‘div’); this.tooltipTitle.split(‘,’).forEach((text) => { this.renderer.appendChild(this.tooltip, this.renderer.createText(text)); this.renderer.appendChild(this.tooltip, this.renderer.createElement(‘br’)); var img2 = document.createElement(‘img’); // Use DOM HTMLImageElement img2.src=”https://stackoverflow.com/questions/54232501/image2.jpg”; img2.alt=”alt text”; this.renderer.appendChild(this.tooltip,img2); this.renderer.appendChild(this.tooltip, this.renderer.createElement(‘br’)); this.renderer.appendChild(document.body, this.tooltip); }); Another layout 5 solved Angular 4 adding an image before each new line using renderer
Angular 4 is a powerful and popular JavaScript framework used for developing web applications. It provides a wide range of features and tools to help developers create dynamic and interactive web applications. One of the features of Angular 4 is the ability to add an image before each new line using the Renderer class. This … Read more
Bro don’t worry. There’s nothing wrong in your site or whatever site you have inspected on. It’s the google chrome’ updated feature to hide html source. When you click on the source link situated in left nav bar, you will get the source code. You don’t need to refresh it. And also view source is … Read more
Obviously $songs is an array of divs. If you need just the first one, then use index: $songs[0]->getElementsByTagName(‘ul’); It would be a good idea to check if $songs array is not empty before that: if (!empty($songs)) { $songs[0]->getElementsByTagName(‘ul’); } Please note that DOMDocument::getElementsByTagName method returns DOMNodeList object which is collection-like. Thus if you want some … Read more
You should use DOMDocument and DOMXPath or something like that, but if you want it done with regexp, for your given html this should do the trick: <?php $html_code=”<a href=”https://stackoverflow.com/napolnye-pokrytiya/” class=”category_cart”> <div class=”category_cart__container”> <div style=”background-image: url(\”/media/filer_public/b6/49/b6491a4d-5c0d-4a0f-aa9c-b32ea39912c6/category-2.jpg\’)” class=”category_cart__thumbnail”></div> <div class=”category_cart__content”> <p class=”category_cart__title”>Напольные покрытия</p> </div> </div> </a> <a href=”http://stackoverflow.com/oboi/” class=”category_cart”> <div class=”category_cart__container”> <div style=”background-image: url(\’/media/filer_public/93/65/9365c3bc-8649-4d9d-932e-144f16ed535c/category-3.jpg\’)” class=”category_cart__thumbnail”></div> <div … Read more
I suggest you edit your question to represent accurately what you are looking for. Based on your comments, if you are looking for the FIRST DIV, use something like this:- x=document.getElementsByTagName(“div”); if (x!= ‘undefined’ && x.length > 0 ) document.write(x[0].id); 2 solved find id of element [closed]
document.querySelectorAll(‘#board > div’).forEach(dv=>console.log(dv.id)) <div id=”board”> <div id=”sss” class=”card”><img src=”https://stackoverflow.com/questions/61471086/img/sss” alt=”sss”></div> <div id=”ssa” class=”card”><img src=”https://stackoverflow.com/questions/61471086/img/sss” alt=”sss”></div> <div id=”ssb” class=”card”><img src=”https://stackoverflow.com/questions/61471086/img/sss” alt=”sss”></div> </div> 0 solved How to get the ids of the children using the parent id?
There are multiple ways to do this. Using XML: <?php $html = “<link rel=”canonical” href=”http://test.com/asdfsdf/sdf/” />”; $xml = simplexml_load_string($html); $attr = $xml->attributes(); print_r($attr); ?> which outputs: SimpleXMLElement Object ( [@attributes] => Array ( [rel] => canonical [href] => http://test.com/asdfsdf/sdf/ ) ) or, using Dom: <?php $html = “<link rel=”canonical” href=”http://test.com/asdfsdf/sdf/” />”; $dom = new DOMDocument; … Read more
There is a missing ” after the javascript function and your code could be modified a little like this – to use event rather than rely upon names or ids <select name=”category” id=”_category” class=”_cateogry” onchange=”submitTheForm(event)” > <option value=””>Please select</option> <?php foreach ($categories as $contents ) {?> <option value=”<?php echo $contents->id;?>” selected=”selected”><?php echo $contents->name;?></option> <?php }?> … Read more
This will work. function Change() { var a = document.getElementsByTagName(“ul”)[0]; a.getElementsByTagName(“li”)[0].innerHTML = “2”; } <ul> <li>1</li> <li>3</li> </ul> <button onclick=”Change();”>Change</button> 1 solved getElementsByTagName() – Only want select elements, not all