You just need to delete the array referenced by del: delete[] del; You are already deleting the arrays referenced by hello and bye: delete[] * del; delete[] * (del + 1); Though this would be more idiomatic: delete[] del[0]; delete[] del[1]; Or even better, avoid using new and delete altogether, taking advantage of modern C++ … Read more
You can delete only what was allocated using the corresponding operator new. String literals have static storage duration. They are not dynamically allocated. According to the C++ Standard 8 Ordinary string literals and UTF-8 string literals are also referred to as narrow string literals. A narrow string literal has type “array of n const char”, … Read more
You would utilize the alloc and init (or more specialized initializer) provided by NSObject. For example, something like the following should work: int fromuser, a; NSMutableArray objectArray = [[NSMutableArray alloc] initWithCapacity:fromuser]; for (a = 0; a < fromuser; a++) { MyObject *obj = [[MyObject alloc] init]; [objectArray addObject:obj]; [obj release]; //If not using ARC } … Read more
a1=a2 //What does this line mean??? = is the assignment operator. This actually assigns the value of the LHS operand to the RHS operand. Here, this line means, assign the value of a2 to a1, i.e, this assigns the a2 pointer to a1. That is, a1 and a2 points to the same memory location. Now, … Read more