First note that your solution is NOT O(n^2), it is more like O(n^4), because for each cell, you look for the largest matrix that can be of size up to O(n^2) itself, so it is totalling to O(n^4). It can be done however in O(n^2): First, define 2 auxillary functions (implemented as matrices): whitesLeft(x,y) = … Read more
I won’t claim that I really know what you are asking, but still I’ll give it shot. To me this seems like a very basic recursion to traverse a tree structure with some weird output while you are doing it. Try it like this: 1. Make an interface for all your classes called INode. This … Read more
To prove that f(n) = Θ(g(n)), you need to prove that there is a nonzero k such that lim (n → ∞) f(n) / g(n) = k In your case, we want to show that lim (n → ∞) lg(n + a) / (lg n) This is an indeterminate form of type ∞ / ∞, … Read more
So, you want to sort an array of custom objects, like this: typedef struct { char c; // a character int i; // a number } pair; Then you can apply a standard function qsort() with a custom compare function like this: int compare(const void *a, const void *b) { pair *p1 = (pair*) a; … Read more
In the discussion below, I demonstrate using a min-heap. A max-heap works the same way, except the root is the largest node rather than the smallest, and parents are larger than their children. Things work the same way, except that you reverse the sense of the comparisons. Insertion into a binary heap follows these rules: … Read more
zipping names with list_price does most of the work for you: result = [] for name, prices in zip(names, list_price): result.append({“name”: name, “size_price”: prices, “size”: size}) 1 solved Data structure in python 2.7 [duplicate]
Here is the greedy algorithm – always the best place to start. allocate all teams IF not all sections covered output -1 stop mark all teams non-critical flag_improved = true WHILE( flag_improved == true ) flag_improved = false find most expensive section find most expensive non-critical team on most expensive section IF team found that … Read more
Is this a class assignment? I have a feeling you’re asking us to do your homework for you. The short answer is that the algorithm is O(n^3). The value of n is read from the console. The outer loop is i = 1 .. n (i is only ever incremented in the loop, i.e. no … Read more
Think very carefully about the code you have for stepping through the list looking for where you can append your new value, especially the last line inside that loop body: while(nodeptr->next){ nodeptr=nodeptr->next; nodeptr->next=newNode; } Were you to actually single-step your code through a debugger, examining the list after each statement, you would see the problem … Read more
Yes, you can and you will run into problems. Since C does not do any boundary checking for you, you are only getting an illusion of it working correctly. You are just getting lucky that no one else is using the piece of memory you are accessing in your *next pointer. So, it may not … Read more
I commented the changed portion and explained why. I didn’t change your code, so that you can understand easily. Try this : #include <stdio.h> #include <stdlib.h> #include <string.h> struct AdjListNode { char *dest; struct AdjListNode* next; }; struct AdjList { struct AdjListNode *head; // pointer to head node of list }; struct Graph { int … Read more
The following class is a quick and dirty implementation with no guarantees for efficiency but it provides the desired behavior. Should someone provide a better answer, I will gladly accept it! class SortedValuesDict: def __init__(self, args=None, **kwargs): “””Initialize the SortedValuesDict with an Iterable or Mapping.””” from collections import Mapping from sortedcontainers import SortedSet self.__sorted_values = … Read more
It depends upon which implementation of stack you are using(Array, LinkedList). Use can use either top=-1 or top=0 to represent empty stack, no as such hard rule. If you are using an Array based stack(e.g A[n]) then better to use top=-1 as array indexes starts from 0 to n-1 for an array of size n … Read more
Yes, this is because the nodes are allocated dynamically. solved Nodes as a pointer
heap sort may be considered as insertion sort or selection sort done on a heap data structure instead of a list? Which one will it be? solved heap sort may be considered as insertion sort or selection sort done on a heap data structure instead of a list? Which one will it be?