[ad_1] This is not black magic. The answer is by saving its data. You do this by putting it in a database, or writing data files. The trick is to write your programs in a way that makes it easy to guarantee that you’ve restored the state you thought you saved. A common approach is … Read more
[ad_1] There are ways to do this in .NET using the ServiceController class and avoiding any interaction with the shell. You can find those here:MSDN ServiceController If you’d prefer to invoke a process through the CMD, you can create two separate processes and call either Thread.Sleep(milliseconds) or Task.Delay(milliseconds) to wait. Additionally, make sure that after … Read more
[ad_1] You declared a as an array of int**, so *a is not a pointer to int but a pointer to pointer to int. Incrementing a pointer adds the size of the data type it points to, so ++*a advances the value at at a[0] by the size of a pointer. What you actually stored … Read more
[ad_1] int column=1; //in your example int row=1;//in your example //for rows for(int i = 0; i<numberofrows; i++) { array[i][column]=0; } //for columns for(int i = 0; i<numberofcolumns; i++) { array[row][i]=0; } 1 [ad_2] solved How to zero specific column of 2d array [closed]
[ad_1] The postfix ++ operator increments the value of a variable after the statement it’s in has been executed. According to C’s precedence rules, the expression will be evaluated something like this: while (*(dst++) = *(src++)); Which will basically: Set the character dst points to to the character src points to. Increment both dst and … Read more
[ad_1] Here’s the offending code in question: if (xflg) index = m * nxy + l*nx + k; fprintf(stdout,”%.1f”,index); else index = m * nxy + k*ny + l; The “if” and “else” sections of this if statement originally had one line each, so adding braces wasn’t strictly necessary. But when you added the call … Read more
[ad_1] it’s equivalent to if (b) { return s1; } else { return s2; } Edit: As Alexey pointed out, I should clarify. return here isn’t the return from your specific function it’s just saying that the statement (b ? s1 : s2) will evaluate to either s1 or s2 based on the value of … Read more
[ad_1] test2.hpp and test.hpp both #include test1.hpp. If the scope of test1_hpp is the whole application, as far as I understand, there can only one include test1.hpp success. Because once included, test1_hpp is defined. The compiler works on translation units (think: individual .cpp files) not the whole application (think: executable). What you call “the scope … Read more
[ad_1] Yes, when you say point3 = (char*)point You are converting the integer pointer point to a character pointer point3. point is designed for pointing at whole integers (which of course are multibyte quantities), while point3 can point at individual bytes. So now point3 points at the individual bytes that point points to, or in … Read more
[ad_1] a.) In the above code, I am not sure what (DateTime?) startDate means? This is saying cast startDate to a DateTime? object. startDate might be a DateTime and for purposes of this for loop, it’s being cast to a nullable DateTime (DateTime?) b.) scorecardMonths on the very last line… sees to be some object.. … Read more
[ad_1] I would: char loop=’y’; while(loop == ‘y’) { //Do your stuff here printf(“do you want to loop? (y/n) “); scanf(” %c”, &loop); if(loop != ‘y’) loop=’n’; } /A 1 [ad_2] solved In C Programming, How do I use a loop to ask user if they want to continue?
[ad_1] The value output by your first rand() call: cout << (rand()%6) << endl ; is not the same as the value tested in your second call: if((rand()%6) <= 3) { You cannot infer the later from the former. To get a grasp of it, replace your if test with: const int alea = rand() … Read more
[ad_1] This is all about noticing patterns in a pyramid. The comment for the first for loop says that it is printing the correct number of spaces before the actual pyramid (i.e. the asterisks). Let’s look at how many spaces there are at each level: * level 0 – 4 spaces *** level 1 – … Read more
[ad_1] I would assume you’d want to compute the cube of a number by using a loop that iterates 3 times. int n, cube, i; printf(“Enter an integer: “); scanf(“%d”,&n); cube = 1; i = 0; while (i < 3) { cube = cube * n; i++; } printf(“%d\n”, cube); 2 [ad_2] solved Our professor … Read more
[ad_1] From the documentation, which can be found here WIA_DPS_DOCUMENT_HANDLING_CAPABILITIES ScannerDeviceDocumentHandlingCapabilities Contains the capabilities of the scanner. The minidriver creates and maintains this property. An application reads this property to determine whether the scanner has a flatbed, document feeder, or duplexer installed. This property is also used to further define the installed features. and The … Read more