you can do something like this: BufferedReader reader = null; try { reader = new BufferedReader(new FileReader(“path”)); String line = null; int count = 0; while ((reader.readLine()) != null && count < 11) { count++; } if (count > 10) { reader = new BufferedReader(new FileReader(“path”)); while ((line = reader.readLine()) != null) { System.out.println(line); } … Read more
To append to existing file use FileWriter with append = true argument in constructor: FileWriter fileWriter= new FileWriter(fileName,true); BufferedWriter bufferWriter = new BufferedWriter(fileWriter); bufferWriter.write(inputString); bufferWriter.close(); Read more about FileWriter here solved writing and reading a txt content using java
This should work. if you are not using an IDE, then maybe you changed your code and didn’t compile again. so you are essentially running an old code with different output? 2 solved Java Input from console giving unexpected values [closed]
You can use Scanner class, which provides a Scanner#nextInt() method to read the next token as int. Now, since your integers are comma(,) separated, you need to set comma(,) as delimiter in your Scanner, which uses whitespace character as default delimiter. You need to use Scanner#useDelimiter(String) method for that. You can use the following code: … Read more
All that adding a throws does it say that the method can throw an Exception, you want to be handling an Exception if it is thrown. To do this, you can wrap the code chunk is a try-catch block. There is no way to stop an Exception from being thrown if it should be thrown, … Read more
InputStream is parent class of all input streams and readers. Classes that have Stream keyword will work with bytes whereas classes which have Reader keyword will work with characters. Buffer is wrapper around these streams to decrease the system calls and increase performance and speed of reading. Non buffered streams return single byte each time … Read more