[Solved] Given the file path find the file extension using Scala?
You could achieve this as follows: import java.nio.file.Paths val path = “/home/gmc/exists.csv” val fileName = Paths.get(path).getFileName // Convert the path string to a Path object and get the “base name” from that path. val extension = fileName.toString.split(“\\.”).last // Split the “base name” on a . and take the last element – which is the extension. … Read more